Question

这是我的代码购买，无论我运行多少次，我得到的就是你输了。代码有什么问题？

import random

# Creates a number to count the amount of plays
count =  1;
# Creates a variable to store the amount of starting money
money = 10;
# Creates a variable telling you how much money you start with
startingCash = "You start with $" + str(money) + "!";

while (count < 101):

    # Variables for the lottery numbers
    lottery1 = random.randint(1,9);
    lottery2 = random.randint(1,9);
    lottery3 = random.randint(1,9);
    lottery4 = random.randint(1,9);

    # Lottery variables in one single variable
    lotteryTotal = (lottery1, lottery2, lottery3, lottery4);

    # Variables for the drawn ticket
    drawn1 = random.randint(1,9);
    drawn2 = random.randint(1,9);
    drawn3 = random.randint(1,9);
    drawn4 = random.randint(1,9);

    # Variable for the drawn ticket in one single variable
    drawnTotal = (drawn1, drawn2, drawn3, drawn4);
    # Variable that changes the money variable so the player has 2 less dollars
    money = money - 2;

==符号似乎被忽略或行为不同。如果它们彼此相等，我希望它if。

    if( drawnTotal == lotteryTotal):
        count = count + 1;
        money = money + 5;
        print ("Lottery Numbers: " + str(lotteryTotal));
        print ("Your Numbers: " + str(drawnTotal));
        print ("You Won $5!");
        input("Press Enter to continue")
    else:
        print ("Lottery Numbers: " + str(lotteryTotal));
        print ("Your Numbers: " + str(drawnTotal));
        print ("You Lost!");
        input("Press Enter to continue");

Answer 1

您的代码正在运行......结果与您的预期不符。

问题在于，要获胜，您需要连续两次生成相同的随机数字序列。那概率是多少？

重复单个1-9位数的概率是9中的1。如果你有两个这样的数字，你有两个1/9概率，它们的复合概率是1/9 * 1/9，或者1/81。如果您有四，就像你的情况一样，你将赢得一次1/9 * 1/9 * 1/9 * 1/9 = 1/6561游戏。

你尝试了“很多次”，但是......你尝试足够次吗？即使在一千场比赛之后，至少赢得一次的概率也不到15％。即使在6561场比赛之后，至少赢得一次的概率也远不及100％ - 实际上它接近三分之二。

我修改它只告诉我胜利的数量，并且只有当你确实获胜时才这样做（MarkyPython的建议）。过了一段时间，它告诉我，

100 won in 686114 games; win rate is 95% of expected.

（顺便说一句，第一场胜利是在29172场比赛之后）。

Answer 2

很好的解释lserni。

Khodexian，如果您愿意增加获胜机会的数量，您可以简单地考虑数字并忽略它们的生成顺序。

例如，

import random

# Creates a number to count the amount of plays
count =  0;
# Creates a variable to store the amount of starting money
money = 10;
# Creates a variable telling you how much money you start with
startingCash = "You start with $" + str(money) + "!";
win, lost = 0, 0
while (win < 100):

    count = count + 1;

    # Variables for the lottery numbers
    lotteryTotal = [random.randint(1,9), random.randint(1,9), random.randint(1,9), random.randint(1,9)]

    # Variable for the drawn ticket in one single variable
    drawnTotal = [random.randint(1,9), random.randint(1,9), random.randint(1,9), random.randint(1,9)]

    # Variable that changes the money variable so the player has 2 less dollars
    money = money - 2;

    if( sorted(lotteryTotal) == sorted(drawnTotal) ):
        money = money + 5;
        print ("Lottery Numbers: " + str(lotteryTotal));
        print ("Your Numbers: " + str(drawnTotal));
        print ("You Won $5!");
        win += 1
    else:
        print ("Lottery Numbers: " + str(lotteryTotal));
        print ("Your Numbers: " + str(drawnTotal));
        print ("You Lost!");
        lost += 1

print ('played {}, won {} and lost {}'.format(count, win, lost))

我得到这样的统计数据，

played 40170, won 100 and lost 40070

制作彩票，似乎我无法获胜

2 个答案: