我已经研究过这个错误的解决方案,但我仍然没有得到它。
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我正在使用ideone.com并仍然收到相同的错误消息(#include <stdio.h>
float calcF(float a, float b, float c);
int main(void)
{
float mag_flux_den, cur, len;
float result;
printf("What is the magnetic flux density in tesla? : ");
scanf("%f", &mag_flux_den);
printf("What is the current in the conductor in Amperes? : ");
scanf("%f", &cur);
printf("What is the length of the conductor in the magnetic field in metres? : ");
scanf("%f", &len);
result = calcF(mag_flux_den, cur, len);
printf("Force on the current carrying conductor: %f", result);
return 0;
}
float calcf(float a, float b, float c) //calculates force on the current carrying conductor{
float F;
F = a * b * c;
return F;
}
)。任何帮助将不胜感激。
答案 0 :(得分:2)
您将函数声明为“calcF”,大写字母为“F”,但您的定义为“calcf”,小写为“f”。确保它们是相同的。
此外,您的代码块底部的函数定义在注释的末尾有一个开括号。
在评论后移动它。
答案 1 :(得分:1)
试试这个:
#include <stdio.h>
#include <cs50.h>
float calcF(float a, float b, float c);
int main(void)
{
float mag_flux_den, cur, len;
float result;
printf("What is the magnetic flux density in tesla? : ");
scanf("%f", &mag_flux_den);
printf("What is the current in the conductor in Amperes? : ");
scanf("%f", &cur);
printf("What is the length of the conductor in the magnetic field in metres? : ");
scanf("%f", &len);
result = calcF(mag_flux_den, cur, len);
printf("Force on the current carrying conductor: %f", result);
return 0;
}
float calcF(float a, float b, float c) //calculates force on the current carrying conductor
{
float F;
F = a * b * c;
return F;
}