显示for循环的所有迭代

Question

我创建了一种方法，可以根据年数计算和显示简单兴趣的值。我想展示所有年份，例如如果年份为5年，我想显示第1,2,3,4,5年的价值

这是我目前的代码

    public static String numbers(String method, double principal, double rate, double years) {

    double simpleInterest = principal + (principal * (rate / 100) * years);
    String interest = "";
    for (double digit = 1; digit <= years; digit++) {
        if (method.equals("Simple")) {
            interest = "Principal: $" + principal + ',' + " Rate: " + rate + "\n" + "Year  Simple Interest Amount\n"
                    + digit + "-->$" + simpleInterest;
        }
    }
    return interest;
}

public static void main(String[] args) {

    System.out.print(numbers("Simple", 5000, 5, 5));
}

我的输出是

Principal: $5000.0, Rate: 5.0
Year  Simple Interest Amount
5.0-->$6250.0

但是我希望它也像前几年那样展示

Principal: $5000.0, Rate: 5.0
Year  Simple Interest Amount
1.0-->$5250.0
2.0-->$5500.0
3.0-->$5750.0
4.0-->$6000.0
5.0-->$6250.0

显示前几年我需要做什么？

Answer 1

您必须每年simpleInterest计算simpleInterest = principal + (principal * (rate / 100) * digit); digit此处year代表+=。

并使用interest运算符将结果连接到return和concat()。 您还可以使用字符串public String concat(String s)方法 以下是此方法的语法：interest = interest.concat(digit + "-->$" + simpleInterest + "\n");。 您可以像这样使用它：public static String numbers(String method, double principal, double rate, double years) { double simpleInterest = principal + (principal * (rate / 100) * years); String interest = ""; System.out.println("Principal: $" + principal + ',' + " Rate: " + rate + "\n"+ "Year Simple Interest Amount\n"); for (double digit = 1; digit <= years; digit++) { if (method.equals("Simple")) { simpleInterest = principal + (principal * (rate / 100) * digit); interest += digit + "-->$" + simpleInterest + "\n"; } } return interest; } public static void main(String[] args) { System.out.print(numbers("Simple", 5000, 5, 5)); }

Principal: $5000.0, Rate: 5.0
Year  Simple Interest Amount

1.0-->$5250.0
2.0-->$5500.0
3.0-->$5750.0
4.0-->$6000.0
5.0-->$6250.0

  

<强>输出：

while

Answer 2

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如果 if (method.equals("Simple")) { interest = "Principal: $" + principal + ',' + " Rate: " + rate + "\n" + "Year Simple Interest Amount\n" + digit + "-->$" + simpleInterest; } 等于interest，则在上面的代码中

重新分配method。所以，返回最后一个赋值。

使用"simple"将新结果连接到+=，或者只将包含每个结果的interest作为单个元素返回，然后迭代它。

Answer 3

public static String numbers（String method，double principal，double rate，double years）         {

        String interest = "";
        for (double digit = 1; digit <= years; digit++)
        {
            if (method.equals(Simple))
            {
                double simpleInterest = principal + (principal * (rate / 100) * digit);
                interest += "Principal: $" + principal + ',' + " Rate: " + rate + "\n" + "Year  Simple Interest Amount\n"
                        + digit + "-->$" + simpleInterest;                   
            }
        }
        return interest;
    }