我有一个使用d3.layout.force
的定向网络。调整this answer,如果连接(连接方向并不重要),我已设法获取节点和链接淡出。
我遇到的问题是,当标记所在的路径的不透明度因mouseover
事件而改变时,能够更改标记的不透明度。
这是包含isConnected
函数的脚本,用于确定连接的节点:
<script>
function bar() {
console.log("click");
force.stop();
force.start();
}
var links = [
{source: "A", target: "D", type: "high"},
{source: "A", target: "K", type: "high"},
{source: "B", target: "G", type: "high"},
{source: "C", target: "A", type: "low"},
{source: "D", target: "K", type: "low"},
{source: "E", target: "A", type: "low"},
{source: "F", target: "B", type: "low"},
{source: "K", target: "J", type: "low"},
{source: "F", target: "A", type: "low"},
{source: "F", target: "I", type: "low"},
{source: "G", target: "H", type: "low"},
{source: "E", target: "K", type: "high"},
{source: "E", target: "G", type: "low"},
{source: "E", target: "F", type: "high"},
{source: "D", target: "E", type: "high"}
];
var nodes = {};
// Compute the distinct nodes from the links.
links.forEach(function(link) {
link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});
var width = 960,
height = 700;
var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(105)
.charge(-775)
.on("tick", tick)
.start();
force.on("start", function () {
console.log("start");
});
force.on("end", function () {
console.log("end");
});
R=18
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
// add defs-marker
svg.append('svg:defs')
.append('svg:marker')
.attr('id', 'end-arrow')
.attr('viewBox', '0 0 10 10')
.attr('refX', 2+R)
.attr('refY', 5)
.attr('markerWidth', 4)
.attr('markerHeight', 4)
.attr('orient', 'auto')
.append('svg:path')
.attr('d', 'M0,0 L0,10 L10,5 z');
var link = svg.selectAll(".link")
.data(force.links())
.enter()
.append("line")
.attr("class", "link")
.attr('marker-end', 'url(#end-arrow)')
;
var node = svg.selectAll(".node")
.data(force.nodes())
.enter().append("g")
.attr("class", "node")
.call(force.drag);
node.append("circle")
.attr("r", R)
.on("mouseover", fade(.1))
.on("mouseout", fade(1))
;
node.append("text")
.attr("x", 0)
.attr("dy", ".35em")
.text(function(d) { return d.name; });
function tick() {
link
.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; })
;
node
.attr("transform", function(d) { return "translate(" + d.x + "," + d.y + ")"; });
}
var linkedByIndex = {};
links.forEach(function(d) {
linkedByIndex[d.source.index + "," + d.target.index] = 1;
});
function isConnected(a, b) {
return linkedByIndex[a.index + "," + b.index] || linkedByIndex[b.index + "," + a.index] || a.index == b.index;
}
function fade(opacity) {
return function(d) {
node.style("stroke-opacity", function(o) {
thisOpacity = isConnected(d, o) ? 1 : opacity;
this.setAttribute('fill-opacity', thisOpacity);
return thisOpacity;
});
link.style("stroke-opacity", function(o) {
return o.source === d || o.target === d ? 1 : opacity;
});
marker.style("opacity", function(o) {
return o.source === d || o.target === d ? 1 : opacity;
});
};
}
</script>
一个与切线相关的问题是如何缩短路径,以便当节点和链路的不透明度消失时,到达每个节点中间的线路不明显。
答案 0 :(得分:1)
由于渲染标记实例的方式,您的方法不可行。将我自己的answers中的一个变为Cannibalizing并引用SVG规范:
11.6.4 Details on how markers are rendered
[...]
标记的渲染效果就好像所引用的“标记”元素的内容被深深地克隆到标记的每个实例的单独的非暴露DOM树中。由于克隆的DOM树是非暴露的,因此SVG DOM不会显示标记的克隆实例。
只有原始标记元素(即声明的<marker>
元素)可以使用CSS进行样式化,而通过属性marker-start
,marker-mid
或marker-end
引用的克隆实例是不可访问,因此不能单独设置样式。
CSS2选择器可以应用于原始(即引用)元素,因为它们是正式文档结构的一部分。 CSS2选择器不能应用于(概念上)克隆的DOM树,因为它的内容不是正式文档结构的一部分。
为了规避这些约束,你可以使用两个定义的marker
元素,第二个是第一个克隆版本,不透明度降低。
// add defs-markers
svg.append('svg:defs').selectAll("marker")
.data([{id:"end-arrow", opacity:1}, {id:"end-arrow-fade", opacity:0.1}])
.enter().append('marker')
.attr('id', function(d) { return d.id; })
.attr('viewBox', '0 0 10 10')
.attr('refX', 2+R)
.attr('refY', 5)
.attr('markerWidth', 4)
.attr('markerHeight', 4)
.attr('orient', 'auto')
.append('svg:path')
.attr('d', 'M0,0 L0,10 L10,5 z')
.style("opacity", function(d) { return d.opacity; });
在fade()
功能中,您可以切换行marker-end
属性以引用相应标记的ID:
link.attr("marker-end", function(o) {
return opacity === 1 || o.source === d || o.target === d
? 'url(#end-arrow)' : 'url(#end-arrow-fade)';
});
请查看以下代码片段以了解正常工作:
function bar() {
console.log("click");
force.stop();
force.start();
}
var links = [
{source: "A", target: "D", type: "high"},
{source: "A", target: "K", type: "high"},
{source: "B", target: "G", type: "high"},
{source: "C", target: "A", type: "low"},
{source: "D", target: "K", type: "low"},
{source: "E", target: "A", type: "low"},
{source: "F", target: "B", type: "low"},
{source: "K", target: "J", type: "low"},
{source: "F", target: "A", type: "low"},
{source: "F", target: "I", type: "low"},
{source: "G", target: "H", type: "low"},
{source: "E", target: "K", type: "high"},
{source: "E", target: "G", type: "low"},
{source: "E", target: "F", type: "high"},
{source: "D", target: "E", type: "high"}
];
var nodes = {};
// Compute the distinct nodes from the links.
links.forEach(function(link) {
link.source = nodes[link.source] || (nodes[link.source] = {name: link.source});
link.target = nodes[link.target] || (nodes[link.target] = {name: link.target});
});
var width = 600,
height = 600;
var force = d3.layout.force()
.nodes(d3.values(nodes))
.links(links)
.size([width, height])
.linkDistance(105)
.charge(-775)
.on("tick", tick)
.start();
force.on("start", function () {
console.log("start");
});
force.on("end", function () {
console.log("end");
});
R=18
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
// add defs-markers
svg.append('svg:defs').selectAll("marker")
.data([{id:"end-arrow", opacity:1}, {id:"end-arrow-fade", opacity:0.1}])
.enter().append('marker')
.attr('id', function(d) { return d.id; })
.attr('viewBox', '0 0 10 10')
.attr('refX', 2+R)
.attr('refY', 5)
.attr('markerWidth', 4)
.attr('markerHeight', 4)
.attr('orient', 'auto')
.append('svg:path')
.attr('d', 'M0,0 L0,10 L10,5 z')
.style("opacity", function(d) { return d.opacity; });
var link = svg.selectAll(".link")
.data(force.links())
.enter()
.append("line")
.attr("class", "link")
.attr('marker-end', 'url(#end-arrow)');
var node = svg.selectAll(".node")
.data(force.nodes())
.enter().append("g")
.attr("class", "node")
.call(force.drag);
node.append("circle")
.attr("r", R)
.on("mouseover", fade(.1))
.on("mouseout", fade(1))
;
node.append("text")
.attr("x", 0)
.attr("dy", ".35em")
.text(function(d) { return d.name; });
function tick() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("transform", function(d) {
return "translate(" + d.x + "," + d.y + ")";
});
}
var linkedByIndex = {};
links.forEach(function(d) {
linkedByIndex[d.source.index + "," + d.target.index] = 1;
});
function isConnected(a, b) {
return linkedByIndex[a.index + "," + b.index] || linkedByIndex[b.index + "," + a.index] || a.index == b.index;
}
function fade(opacity) {
return function(d) {
node.style("stroke-opacity", function(o) {
thisOpacity = isConnected(d, o) ? 1 : opacity;
this.setAttribute('fill-opacity', thisOpacity);
return thisOpacity;
});
link.style("stroke-opacity", function(o) {
return o.source === d || o.target === d ? 1 : opacity;
});
link.attr("marker-end", function(o) {
return opacity === 1 || o.source === d || o.target === d
? 'url(#end-arrow)' : 'url(#end-arrow-fade)';
});
};
}
.node circle {
fill: #DDD;
stroke: #777;
stroke-width: 2px;
}
.node text {
font-family: sans-serif;
text-anchor: middle;
pointer-events: none;
user-select: none;
-webkit-user-select: none;
}
.link {
stroke: #88A;
stroke-width: 4px;
}
text {
font: 18px sans-serif;
pointer-events: none;
}
#end-arrow {
fill: #88A;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.5/d3.min.js"></script>