如果两个参数匹配，则从对象中删除重复项

Question

我有一个带有两个参数ml_successor和ml_predecessor的对象， 如果这些参数都匹配，我想从对象中删除重复项。

下面是我尝试的代码，但即使其中一个参数（ml_successor或ml_predecessor）与其他项匹配，也会删除项目。

var depArr = [{
    "ml_predecessor": "0e1cea11-4af4-4bb9-9269-8a1eecc3e848",
    "ml_successor": "c67c5b33-8e5c-48fc-9178-50eb8379426c"
}, {
    "ml_predecessor": "0e1cea11-4af4-4bb9-9269-8a1eecc3e848",
    "ml_successor": "db1cfd99-1e07-47b7-b9e0-bb84420f454e"
}, {
    "ml_predecessor": "0e1cea11-4af4-4bb9-9269-8a1eecc3e848",
    "ml_successor": "c67c5b33-8e5c-48fc-9178-50eb8379426c"
}, {
    "ml_predecessor": "db1cfd99-1e07-47b7-b9e0-bb84420f454e",
    "ml_successor": "73133d97-b094-41dd-ba2c-c93502a68bfa"
}, {
    "ml_predecessor": "0e1cea11-4af4-4bb9-9269-8a1eecc3e848",
    "ml_successor": "db1cfd99-1e07-47b7-b9e0-bb84420f454e"
}, {
    "ml_predecessor": "db1cfd99-1e07-47b7-b9e0-bb84420f454e",
    "ml_successor": "73133d97-b094-41dd-ba2c-c93502a68bfa"
}];
var dupes = {},
    dupes1 = {},
    singles = [];

$.each(depArr, function(i, el) {
    if (!dupes[el.ml_predecessor] && !dupes1[el.ml_successor]) {
        dupes[el.ml_predecessor] = true;
        dupes1[el.ml_successor] = true;
        singles.push(el);
    }
});

Answer 1

使用此：

const singles = [];
const inArray = (array, item) => {
  return $.grep(array, (arrayItem) => { 
    return arrayItem.ml_predecessor === item.ml_predecessor  &&  arrayItem.ml_successor === item.ml_successor;
  }).length > 0;
};
$.each(depArr, (index, item) => {
  if (!inArray(singles, item)) {
      singles.push(item);
  }
});