如何在另一个选项卡上获取新URL然后再进行处理？

Question

测试场景：

1. 使用网址＆＃34; www.xyz.com＆＃34;
注册您的帐户
2. 验证注册成功消息。
3. 现在想要打开另一个标签并获取另一个新网址＆＃34; http://www.gmail.com/＆＃34;通过单击激活链接激活注册。

目前，我可以打开另一个标签，但这些标签无法获取Gmail网址。此外，我正在使用关键字驱动框架。

那么，任何人都可以帮我解决它吗？

方法中的条件：

    if(operation.equalsIgnoreCase("urlOnNewTab")){
                    temp.sendKeys(Keys.CONTROL+"t");
                    ArrayList<String> tab = new ArrayList<String>(driver.getWindowHandles());
                    driver.switchTo().window(tab.get(1));

                    /*String selectLinkOpeninNewTab = Keys.chord(Keys.CONTROL,Keys.RETURN); 
                    temp.sendKeys(selectLinkOpeninNewTab);*/

                    driver.get(value);

                    if (operation.equalsIgnoreCase("SendKey")) {
                        temp.sendKeys(value);
                    }

                    driver.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);
                    if (operation.equalsIgnoreCase("Click")) {
                        temp.click();
                    }
                    if (operation.equalsIgnoreCase("Verify")) {
                        System.out.println("Verify--->" + temp);
                        temp.isDisplayed();
                    }
                }


public WebElement getElement(String locator, String objectName)
            throws Exception {
        WebElement temp = null;

        System.out.println("Locator-->" + locator);
        if (locator.equalsIgnoreCase("id")) {
            temp = driver.findElement(By.id(objectName));

        } else if (locator.equalsIgnoreCase("xpath")) {
            temp = driver.findElement(By.xpath(objectName));
            System.out.println("xpath temp ----->" + temp);
        } else if (locator.equalsIgnoreCase("name")) {
            temp = driver.findElement(By.name(objectName));
        }else if (locator.equalsIgnoreCase("linkText")) {
            temp = driver.findElement(By.linkText(objectName));
        }else if (locator.equalsIgnoreCase("cssSelector")) {
            temp = driver.findElement(By.cssSelector(objectName));
        }

        return temp;

Answer 1

我没有得到任何人的反馈，但我尝试了下面的代码，根据我的问题它对我有用。

<强>代码：

 if(operation.equalsIgnoreCase("urlOnNewTab")){
                    temp.sendKeys(Keys.CONTROL+"t");
                    driver.get(value);
                    if (operation.equalsIgnoreCase("SendKey")) {
                        temp.sendKeys(value);
                    }

                    driver.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);
                    if (operation.equalsIgnoreCase("Click")) {
                        temp.click();
                    }
                    if (operation.equalsIgnoreCase("Verify")) {
                        System.out.println("Verify--->" + temp);
                        temp.isDisplayed();
                    }
                }

    public WebElement getElement(String locator, String objectName)
                throws Exception {
            WebElement temp = null;

            System.out.println("Locator-->" + locator);
            if (locator.equalsIgnoreCase("id")) {
                temp = driver.findElement(By.id(objectName));

            } else if (locator.equalsIgnoreCase("xpath")) {
                temp = driver.findElement(By.xpath(objectName));
                System.out.println("xpath temp ----->" + temp);
            } else if (locator.equalsIgnoreCase("name")) {
                temp = driver.findElement(By.name(objectName));
            }else if (locator.equalsIgnoreCase("cssSelector")) {
                temp = driver.findElement(By.cssSelector(objectName));
            }

            return temp;