Question

我已经看到了几个反思的例子，但似乎无法让它们为我的确切问题而工作......

我的3个班级......

 public class Row
    {
        public string Cell1  = "cat";//{ get; set; }
        public string Cell2 = "fish"; //{ get; set; }
        public string Cell3 = "dog";  //{ get; set; }


    }

    public class Grid
    {
        public Row Row1 = new Row();
        public Row Row2 = new Row();
        public Row Row3 = new Row();

    }

    public class SetOfGrids
    {
        public Grid g1 = new Grid();
        public Grid g2 = new Grid();
    }

我如何获得价值......

SetOfGrids sog = new SetOfGrids();
 MessageBox.Show(sog.g1.Row1.Cell1);

我觉得可能有用的链接的getproperty函数......

public Object GetPropValue(String name, Object obj) {
    foreach (String part in name.Split('.')) {
        if (obj == null) { return null; }

        Type type = obj.GetType();
        PropertyInfo info = type.GetProperty(part);
        if (info == null) { return null; }

        obj = info.GetValue(obj, null);
    }
    return obj;
}

我希望如何获得值...（我得到一个空的异常错误。）

 string PathToProperty = "sog.g1.Row1.Cell1";
 string s = GetPropValue(PathToProperty, sog).ToString;
 MessageBox.Show(s);

结果应为“cat2”

更新按照建议将行代码更改为以下内容。

public class Row
    {
        public string Cell1  { get; set; }
        public string Cell2 { get; set; }
        public string Cell3 { get; set; }
       public  Row()
        {
            this.Cell1 = "cat";
            this.Cell2 = "dog";
            this.Cell3 = "fish";
        }

    }

Answer 1

问题是你问方法GetProperty来获取字段，而不是属性。尝试将字段更改为属性或使用GetField方法。

Answer 2

此：

using System;
using System.Linq;
using System.Net;
using System.Reflection;

namespace Test
{
    public class Row
    {
        public string Cell1 { get; set; } 
        public string Cell2 { get; set; } 
        public string Cell3 { get; set; }  
    }

    public class Grid
    {
        public Row Row1 { get; set; } 
        public Row Row2 { get; set; } 
        public Row Row3 { get; set; } 
    }

    public class SetOfGrids
    {
        public Grid g1 { get; set; } 
        public Grid g2 { get; set; } 
    }

    class Program
    {
        public static object GetPropValue(string name, object obj)
        {
            foreach (string part in name.Split('.'))
            {
                if (obj == null) { return null; }

                var type = obj.GetType();
                var info = type.GetProperty(part);

                if (info == null) { return null; }

                obj = info.GetValue(obj, null);
            }

            return obj;
        }

        public static void Main()
        {
            SetOfGrids sog = new SetOfGrids
            {
                g1 = new Grid { Row1 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row2 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row3 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" } },
                g2 = new Grid { Row1 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row2 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row3 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" } }
            };

            string PathToProperty = "g1.Row1.Cell1";

            object s = GetPropValue(PathToProperty, sog);

            Console.WriteLine(s);
            Console.ReadLine();
        }
    }
}

工作正常。请注意，我将所有字段都更改为实际属性，并删除了字符串的第一部分，因为“sog”。是变量名，而不是属性。

使用字符串获取对象属性

2 个答案: