Question

我使用以下代码来解析json对象中的json数组。

JSONObject notificationResponse = new JSONObject(response.toString());
JSONObject value = new JSONObject(notificationResponse.getString("value"));
JSONArray details = value.optJSONArray("details");
final int numberOfItems = details.length();

for (int i =0; i <= numberOfItems; i++ ){
JSONObject jsonObjects = details.getJSONObject(i);
String text = jsonObjects.getString("text");
String date = jsonObjects.getString("date & time");
Log.d(TAG,text + " " +date);
  }

 } catch (Exception e) {
         e.printStackTrace();
   }

以下是我的json。

{"status":1,"value":{"details":[{"text":"sample", "date & time":"12-NOV-15 3:30pm"}]}}

out of range

处的我的代码JSONObject jsonObjects = details.getJSONObject(i);例外情况

Answer 1

使用

for (int i =0; i < numberOfItems; i++ )
{
JSONObject jsonObjects = details.getJSONObject(i);
String text = jsonObjects.getString("text");
String date = jsonObjects.getString("date & time");
 Log.d(TAG,text + " " +date);
 }

而不是

   for (int i =0; i <= numberOfItems; i++ )
   {
   JSONObject jsonObjects = details.getJSONObject(i);
   String text = jsonObjects.getString("text");
   String date = jsonObjects.getString("date & time");
   Log.d(TAG,text + " " +date);
  }

Answer 2

请试试这个使用i < numberOfItems;代替i <= numberOfItems;

JSONObject notificationResponse = new JSONObject(response.toString());
JSONObject value = new JSONObject(notificationResponse.getString("value"));
JSONArray details = value.optJSONArray("details");
final int numberOfItems = details.length();

for (int i =0; i < numberOfItems; i++ ){
JSONObject jsonObjects = details.getJSONObject(i);
String text = jsonObjects.getString("text");
String date = jsonObjects.getString("date & time");
Log.d(TAG,text + " " +date);
  }

 } catch (Exception e) {
         e.printStackTrace();
   }

希望这有助于你

Answer 3

从你的for循环中

remove =

for (int i =0; i < numberOfItems; i++ )

JsonArray索引将从0开始，因此length()将返回（总大小为1）

Answer 4

尝试使用以下内容：

for (int i =0; i < numberOfItems; i++ ){
JSONObject jsonObjects = details.getJSONObject(i);
String text = jsonObjects.getString("text");
String date = jsonObjects.getString("date & time");
Log.d(TAG,text + " " +date);
}

Answer 5

由于你是以 i = 0 开始循环，因此条件应修改如下：

for (int i =0; i < numberOfItems; i++ ){
}

而不是

for (int i =0; i <= numberOfItems; i++ ){
}

解析json数组时超出范围错误的索引

5 个答案: