Question

我想从这个子查询返回第二项：

set GrowerNumber =(select top 1 tea_no
  from ktda_file
  where ktda_file.fosa_acno=customer.fosa_acno)

Answer 1

GrowerNumber = (
  select top 1
    tea_no
  from
    (
      select top 2
        tea_no
      from
        ktda_file
      where ktda_file.fosa_acno=customer.fosa_acno
    ) as a
  order by
    tea_no desc
)

Answer 2

试试这个

WITH CTE AS
( 
 SELECT top 2 tea_no  from ktda_file
 WHERE ktda_file.fosa_acno=customer.fosa_acno
 ORDER BY tea_no ASC
)     
SELECT TOP 1 tea_no  FROM CTE ORDER BY tea_no DESC

Answer 3

SELECT *
FROM customer
OUTER APPLY (
    SELECT
        Item1 = MAX(CASE WHEN t.RowNum = 1 THEN t.tea_no END),
        Item2 = MAX(CASE WHEN t.RowNum = 2 THEN t.tea_no END)
    FROM (
        SELECT tea_no, RowNum = ROW_NUMBER() OVER (ORDER BY tea_no)
        FROM ktda_file
        WHERE ktda_file.fosa_acno = customer.fosa_acno
    ) t
    WHERE RowNum < 3
) t2

Answer 4

也许这会对你有所帮助：

(select tea_no from (select row_number() over ( order by tea_no asc) as rowID,  tea_no from ktda_file where ktda_file.fosa_acno=customer.fosa_acno)x where rowID = 2)

Answer 5

嗨，你需要做这样的事情（正如Ivan所说，你的查询中没有订单，那么第二个是什么？）尽管如此，假设它是tea_no ......

GrowerNumber = (Select tea_no  from (select row_number() over (order by tea_no) as row
    from ktda_file where ktda_file.fosa_acno=customer.fosa_acno) as orderedlist
    where row = 2)

从子查询返回第二项

5 个答案: