我需要获得一个包含三个字符而不是一个字符的列值。
这是我的要求:f = j.merge({
hasRecievedData: true,
data: m.get("staffs").map(function(x){
return x.set("hideDetails",true);
})
});
这就是结果:
我需要select rank() over (order by 1,2,32 ) from dual
而不是001
感谢您的帮助
答案 0 :(得分:1)
使用LPAD()
:
SELECT LPAD( '1', 3, '0' ) FROM DUAL;
输出:
001
将其包裹在您的查询中:
SELECT LPAD( rank() over (order by 1,2,32 ), 3, '0' )
FROM DUAL;
答案 1 :(得分:1)
可能是最直接的解决方案:
select to_char(rank() over (order by 1,2,32 ),'fm000') from dual
答案 2 :(得分:0)
IMO,您可以像这样使用! not a valid url: https://docs.google.com/spreadsheets/d/1101qb2Vz0ZW7cjnTpjBpOP71wy7iOcXdqPug0F37xYA/edit#gid=0
Traceback (most recent call last):
File "C:/Users/Abdul/PycharmProjects/examples/main.py", line 4, in <module>
reader = GSpreadsheet(url=url)
File "C:\Python27\lib\site-packages\gspreadsheet\gspreadsheet.py", line 191, in __init__
self.key = re.search(r'key=([0-9a-zA-Z\-]+)', url).group(1)
AttributeError: 'NoneType' object has no attribute 'group'
:
SUBSTR()
尚未测试;)。
答案 3 :(得分:0)
select lpad(rank() over (order by 1,2,32 ),3,0) from dual;
select substr('00' || rank() over (order by 1,2,32 ),1,3) from dual;