Question

我正在尝试制作一个必须让我能够在同一网络中找到本地设备的项目以及有关其IP，mac地址和供应商的信息。到目前为止一切都很好但问题是我通过此代码重新表达了它只发现移动电话，并以某种方式看不到我的笔记本电脑？我测试了这个代码，它只显示我的平板电脑和手机，但没有电脑。如果你有任何建议请现在就说。谢谢。这是我的代码belove。

//This class is my pinger class

public class DiscoverRunner implements Runnable {
private List<InetAddress> results;

private String subnet;
private Integer startAdd;
private Integer numAdds;

public DiscoverRunner(String subnet, Integer start, Integer steps) {
    this.subnet = subnet;
    this.startAdd = start;
    this.numAdds = steps;
    results = new LinkedList<InetAddress>();
}




@Override
public void run() {


    int timeout=4000;
       for (int i=startAdd;i<startAdd+numAdds;i++){

           String host=subnet +"." + i;
           try {
               InetAddress a = InetAddress.getByName(host);


            if (a.isReachable(timeout)){

                results.add(a);
                //System.out.println(host + " is reachable");
               }
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
       }

}

public List<InetAddress> getResults(){
    return results;
}

}

这是我的另一个类，我处理线程来执行

public class Pinger {

private static final int NUMTHREADS = 254;
public static String myMacAddress = "";

public static ArrayList<Device> getDevicesOnNetwork(String subnet) throws IOException {
    LinkedList<InetAddress> resAddresses = new LinkedList<InetAddress>();
    DiscoverRunner[] tasks = new DiscoverRunner[NUMTHREADS];

    Thread[] threads = new Thread[NUMTHREADS];


    //Create Tasks and treads
    for (int i = 0; i < NUMTHREADS; i++) {
        tasks[i] = new DiscoverRunner(subnet,i,1);
        threads[i] = new Thread(tasks[i]);
    }
    //Starts threads
    for (int i = 0; i < NUMTHREADS; i++) {
        threads[i].start();
    }

    for (int i = 0; i < NUMTHREADS; i++) {
        try {
            threads[i].join();
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
    }

    for (int i = 0; i < NUMTHREADS; i++) {
        for (InetAddress a : tasks[i].getResults()) {
            try {
                a = InetAddress.getByName(a.getHostAddress());

            } catch (UnknownHostException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            resAddresses.add(a);
        }

    }

    ArrayList<Device> foundDev = new ArrayList<Device>(resAddresses.size());


    for (InetAddress a : resAddresses) {
        foundDev.add(new Device(a.getHostAddress(), getMacFromArpCache(a.getHostAddress()), a.getCanonicalHostName(), getVendorName(getMacFromArpCache(a.getHostAddress()))));
    }


    return foundDev;
}

/**
 * Try to extract a hardware MAC address from a given IP address using the
 * ARP cache (/proc/net/arp).<br>
 * <br>
 * We assume that the file has this structure:<br>
 * <br>
 * IP address       HW type     Flags       HW address            Mask     Device
 * 192.168.18.11    0x1         0x2         00:04:20:06:55:1a     *        eth0
 * 192.168.18.36    0x1         0x2         00:22:43:ab:2a:5b     *        eth0
 *
 * @param ip
 * @return the MAC from the ARP cache
 */
public static String getMacFromArpCache(String ip) {


    if (ip == null) {
        return null;
    }

    BufferedReader br = null;

    try {


        br = new BufferedReader(new FileReader("/proc/net/arp"));

        String line;
        while ((line = br.readLine()) != null) {
            String[] splitted = line.split(" +");


            if (splitted != null && splitted.length >= 4 && ip.equals(splitted[0])) {
                // Basic sanity check
                String mac = splitted[3];

                if (mac.matches("..:..:..:..:..:..")) {
                    return mac;

                } else {
                    return null;

                }
            }


        }
        return myMacAddress;
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        try {
            if (br != null) {
                br.close();
            }

        } catch (IOException e) {
            e.printStackTrace();
        }
    }
    return null;
}


public static String getVendorName(String MacAddress) throws IOException {

    try {
        URL url = new URL("http://api.macvendors.com/" + MacAddress);

        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setRequestMethod("POST");

        InputStream in = new BufferedInputStream(conn.getInputStream());
        String vendorName = org.apache.commons.io.IOUtils.toString(in, "UTF-8");


        return vendorName;
    } catch (MalformedURLException e) {


        return null;
    } catch (ProtocolException e) {

        return null;
    } catch (IOException e) {

        return null;
    }
}

}

Answer 1

这个ping就像在命令行上一样，也许你可以改变你的编码风格。

try {
        Runtime rt = Runtime.getRuntime();
        Process p = rt.exec("ping 192.168.0.142");

        BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream()));
        String line;
        while ((line = input.readLine()) != null) {
            System.out.println(line);
            p.destroy();
            break;
        }
        input.close();
} catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
}

发现本地网络设备＆amp; IPs Programmaticaly

1 个答案: