我无法解析JSON，但我可以从网上查看JSON

Question

我无法解析JSON。 我的ParseJSon

的getJSON

{"server_response":{"id":"1","email":"josephine_locsin@gmail.com","password":"7c4a8d09ca3762af61e59520943dc26494f8941b","first_name":"Josephine","last_name":"Locsin","title":"Chief Executive Officer, Tumandok Crafts Industries","skype_name":"echo123","filename":"1.jpg","birthdate":"1979-04-10","about_me":"Chief Executive Officer, Tumandok Crafts Industries And Former President, Association For Negros Producers (ANP)","facebook":null,"twitter":null,"google_plus":null,"linked_in":null,"address":"Bago City","gender":"Female","civil_status":"Married","user_type":"client","client_type_id":"1","province_id":"10","is_online":"2","is_activated":"1","last_activity":"2016-02-26 11:29:36","date_registered":null,"agencies":false}}

Answer 1

你的server_response不是jsonArray，它是JsonObject

Answer 2

在doInBackground中，为什么要返回null return = null。相反，你必须返回响应。所以改变它