Question

我在$members

中存储了以下数组

array(3) { 
[0]=> array(2) { 
    ["index"]=> string(1) "1" 
    ["routePartitionName"]=> string(20) "US-555-foop-GWRoutes" } 
[1]=> array(2) { 
    ["index"]=> string(1) "2" 
    ["routePartitionName"]=> string(27) "Cluster DN Presence Allowed" } 
[2]=> array(2) { 
    ["index"]=> string(1) "3" 
    ["routePartitionName"]=> string(26) "Cluster DN Presence Denied" } 
}

我试图在foreach循环中将它嵌入到另一个数组中。但是，它似乎将$members变量评估为文本。

$programTags[] = array(
    "name"=>"$cssname",
    "description"=>"$cssdescription",
    "members"=>"$members");

如何扩展变量，从而创建多维数组？

Answer 1

Remove the quotes from $members variable, it convert it into string.
$programTags[] = array(
    "name"=>"$cssname",
    "description"=>"$cssdescription",
    "members"=>$members);

Answer 2

使用嵌套的$output .= '<div>'.$rN.'</div>';

foreach

exapmple：

foreach($members as $array)
{
    //$array is array variable .

     foreach($array as $values)
     {
        //your code here
     }
}

然后再宣布$member = array(3) { [0]=> array(2) { ["index"]=> string(1) "1" ["routePartitionName"]=> string(20) "US-555-foop-GWRoutes" } [1]=> array(2) { ["index"]=> string(1) "2" ["routePartitionName"]=> string(27) "Cluster DN Presence Allowed" } [2]=> array(2) { ["index"]=> string(1) "3" ["routePartitionName"]=> string(26) "Cluster DN Presence Denied" } }，

foreach

PHP - 从变量epanded的多维数组

2 个答案: