下面这段代码在单击html链接时打开一个新片段,我想关闭当前片段,以便它不会在后台保持打开状态。
protected boolean isURLMatching(String url) {
url = "http://bakara2.com";
// some logic to match the URL would be safe to have here
return true;
}
protected void openNextActivity() {
Fragment fragment = null;
fragment = new bakara2();
replaceFragment(fragment);
}
public void replaceFragment(Fragment someFragment) {
FragmentTransaction transaction = getFragmentManager().beginTransaction();
transaction.replace(R.id.frame_container, someFragment);
transaction.addToBackStack(null);
transaction.commit();
}
答案 0 :(得分:0)
getActivity().getSupportFragmentManager().beginTransaction().remove(this).commit();
答案 1 :(得分:0)
尝试这样做一次!
getActivity().getFragmentManager().popBackStack();
答案 2 :(得分:0)
@Garry popBackStack()因为@Jusna Leema添加片段而无法正常工作:
transaction.replace(R.id.frame_container, someFragment);
transaction.addToBackStack(null);
transaction.commit();
<强> transaction.addToBackStack(空); 强>
简单的删除片段应该可以工作。