Question

使用以下代码，我不断收到以下错误：

关键字＆＃39; DECLARE＆＃39;附近的语法不正确关键字＆＃39; AS＆＃39;附近的语法不正确。

非常感谢任何帮助！

DROP PROCEDURE [dbo].[csp_WellTestValidationResultsTEST_GetData]
GO
CREATE PROCEDURE [dbo].[csp_WellTestValidationResultsTEST_GetData]

DECLARE @ColumnName varchar(max);       --Column Name that Maps to AF Attribute
DECLARE @ColumnValue varchar(max);      --Specific Value for that Column
DECLARE @LeftNumber varchar(50) = SUBSTRING(@ColumnValue,0,CHARINDEX('-',@ColumnValue,0));
DECLARE @RightNumber varchar(50) = SUBSTRING(@ColumnValue,CHARINDEX('-',@ColumnValue,0)+1,LEN(@ColumnValue));
DECLARE @API varchar(50) = SUBSTRING(@ColumnName,0,CHARINDEX('-',@ColumnName,0));


AS
BEGIN
SET NOCOUNT ON;

IF (@ColumnName = 'API14-2')
       Exec('Select * from dbo.SSIS_RTRM_WellTestValidationResults where '+@API+' = '+@LeftNumber+' OR '+@API+' = '+@RightNumber+' order by TestDate Desc')   
Else 
    Select * From dbo.SSIS_RTRM_WellTestValidationResults where WellId = ''
  END

Answer 1

要将变量传递给sporc，请使用语法create procedure {schema.procedure_name} {@ variable1} {variable1_data_type}，{@ variable2} {variable2_data_type} 如 {SPROC here}

如果您想要一个变量的默认值，这也使变量成为可选项，{variable} {vairable_data_type} = {variable_default_value}

这仅适用于调用sproc时传递的变量。您在sproc中声明的sproc中定义的任何变量。

CREATE PROCEDURE [dbo].[csp_WellTestValidationResultsTEST_GetData]
@ColumnName varchar(max);       --Column Name that Maps to AF Attribute
,@ColumnValue varchar(max);      --Specific Value for that Column
AS
DECLARE @LeftNumber varchar(50) = SUBSTRING(@ColumnValue,0,CHARINDEX('-',@ColumnValue,0));
DECLARE @RightNumber varchar(50) = SUBSTRING(@ColumnValue,CHARINDEX('-',@ColumnValue,0)+1,LEN(@ColumnValue));
DECLARE @API varchar(50) = SUBSTRING(@ColumnName,0,CHARINDEX('-',@ColumnName,0));

Answer 2

As＆＃39; Gordon Linoff＆＃39;指出，你的创建过程语句应该是

CREATE PROCEDURE [dbo].[csp_WellTestValidationResultsTEST_GetData]

AS
BEGIN
SET NOCOUNT ON;

DECLARE @ColumnName varchar(max);       --Column Name that Maps to AF Attribute
........

另一方面，我不确定您是否可以在同一语句中声明和赋值，可能需要将其替换为：

DECLARE @LeftNumber varchar(50);
SET @LeftNumber = SUBSTRING(@ColumnValue,0,CHARINDEX('-',@ColumnValue,0));

等等

关键字＆＃39; DECLARE＆＃39;附近的语法不正确。关键字＆＃39; AS＆＃39;附近的语法不正确

2 个答案: