我的性能测试流程需要JAMon监视器完成以下步骤:
但以下情况不起作用(步骤4无效)。
你能为我提供一个解决方法吗?
使用代码证明:
public class Main {
protected static void monitorSomething() throws InterruptedException, IOException, ClassNotFoundException{
Monitor outerMonitor = MonitorFactory.start("outerMonitor");
for (int i=1; i<=10; i++) {
Monitor inner = MonitorFactory.start("myInnerMonitor");
Monitor serializedMonitorSource = MonitorFactory.start("serializedMonitor");
Thread.sleep(100+i);
byte[] serialized = serialize( serializedMonitorSource );
Monitor serializedMonitorDestination = (Monitor)deserialize( serialized );
serializedMonitorDestination.stop();
inner.stop();
}
outerMonitor.stop();
MonitorFactory.start("mySecondMonitor")
.stop();
}
protected static void printPerformanceMeasurements(){
for( Object monitor: MonitorFactory.getMap().values() ){
System.out.println( monitor );
}
}
public static void main(String[] args) throws InterruptedException, IOException, ClassNotFoundException {
monitorSomething();
printPerformanceMeasurements();
}
private static byte[] serialize(Serializable serializable) throws IOException {
try (ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutput out = new ObjectOutputStream(bos)) {
out.writeObject(serializable);
byte[] messageBytes = bos.toByteArray();
return messageBytes;
}
}
private static Object deserialize(byte[] bytes) throws IOException, ClassNotFoundException{
try (ByteArrayInputStream bis = new ByteArrayInputStream(bytes);
ObjectInput in = new ObjectInputStream(bis)) {
return in.readObject();
}
}
}
输出:
JAMon Label=myInnerMonitor, Units=ms.: (LastValue=114.0, Hits=10.0, Avg=114.2, Total=1142.0, Min=105.0, Max=136.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:38 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=outerMonitor, Units=ms.: (LastValue=1143.0, Hits=1.0, Avg=1143.0, Total=1143.0, Min=1143.0, Max=1143.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:39 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=mySecondMonitor, Units=ms.: (LastValue=0.0, Hits=1.0, Avg=0.0, Total=0.0, Min=0.0, Max=0.0, Active=0.0, Avg Active=1.0, Max Active=1.0, First Access=Thu Feb 25 22:01:39 EET 2016, Last Access=Thu Feb 25 22:01:39 EET 2016)
JAMon Label=serializedMonitor, Units=ms.: (LastValue=0.0, Hits=0.0, Avg=0.0, Total=0.0, Min=1.7976931348623157E308, Max=-1.7976931348623157E308, Active=10.0, Avg Active=0.0, Max Active=0.0, First Access=Thu Jan 01 02:00:00 EET 1970, Last Access=Thu Jan 01 02:00:00 EET 1970)
JAMon Label=com.jamonapi.Exceptions, Units=Exception: (LastValue=0.0, Hits=0.0, Avg=0.0, Total=0.0, Min=1.7976931348623157E308, Max=-1.7976931348623157E308, Active=0.0, Avg Active=0.0, Max Active=0.0, First Access=Thu Jan 01 02:00:00 EET 1970, Last Access=Thu Jan 01 02:00:00 EET 1970)
请注意,没有测量serializedMonitor(active = 10)
答案 0 :(得分:0)
解决方法是不是序列化整个Monitor对象,而只是序列化开始时刻。在测量点,您可以反序列化该时刻并计算从现在开始的时差。然后将计算值添加到MonitorFactory统计信息池。
您获得时间执行统计信息(min,max,avg)。缺点是您丢失了活动执行的统计信息。
示例代码:
// Monitor serializedMonitorSource = MonitorFactory.start("serializedMonitor");
Date measuringStartOriginal = new Date();
byte[] serialized = serialize( measuringStartOriginal );
Thread.sleep(100+i);
// Monitor serializedMonitorDestination = (Monitor)deserialize( serialized );
Date measuringStartDeserialized = (Date)deserialize( serialized );
// serializedMonitorDestination.stop();
Date measuringEnd = (new Date());
long timeDifference = measuringEnd.getTime() - measuringStartDeserialized.getTime();
MonitorFactory.add( "timeDifference", "ms", timeDifference );
结果:
JAMon Label=timeDifference, Units=ms: (LastValue=110.0, Hits=10.0, Avg=106.3, Total=1063.0, Min=102.0, Max=110.0, Active=0.0, Avg Active=0.0, Max Active=0.0, First Access=Mon Feb 29 10:43:57 EET 2016, Last Access=Mon Feb 29 10:43:58 EET 2016)