Question

MySQL的：

我可以使用此查询将数据从另一个表插入到一个表中：

INSERT INTO design (id_event,id_theme,color_main,color_bg)  
SELECT '123',
       '5',
       color_main,
       color_bg 
FROM theme 
WHERE id_theme='5'

我也可以更新它，如下所示：

UPDATE design INNER JOIN theme ON design.id_theme=theme.id_theme
SET design.color_main=theme.color_main, design.color_bg=theme.color_bg
WHERE id_event='123'

是否可以将这两个查询合并为一个，如下所示：

INSERT INTO design (id_event,id_theme,color_main,color_bg) 
SELECT '123','5',color_main,color_bg FROM theme WHERE id_theme='5'
ON DUPLICATE KEY UPDATE id_theme='5',color_main=???,color_bg=???

感谢。

Answer 1

您可以使用：

   function addDeleteBtn(x, y, w){
        $(".deleteBtn").remove();
        var btnLeft = x;
        var btnTop = y - 30;
        var widthadjust=w/2;
        btnLeft=widthadjust+btnLeft-1
        var deleteBtn = '<img src="https://www.funagain.com/images/old/common/delete-icon.png" class="deleteBtn" ' +
                'style="position:absolute;top:'+btnTop+'px;right:'+btnLeft+'px;cursor:pointer;"/>';
        $(".canvas-container").append(deleteBtn);
    }

    canvas.on('object:selected',function(e){
        addDeleteBtn(e.target.oCoords.mt.x, e.target.oCoords.mt.y, e.target.width);
    });

    canvas.on('mouse:down',function(e){
        if(!canvas.getActiveObject())
        {
            $(".deleteBtn").remove();
        }
    });

    canvas.on('object:modified',function(e){
        addDeleteBtn(e.target.oCoords.mt.x, e.target.oCoords.mt.y, e.target.width);
    });

    canvas.on('object:moving',function(e){
        $(".deleteBtn").remove();
    });

    $(document).on('click',".deleteBtn",function(){
        if(canvas.getActiveObject())
        {
            canvas.remove(canvas.getActiveObject());
            $(".deleteBtn").remove();
        }
    });

从另一个表插入，并在一个查询中更新密钥是否存在？

1 个答案: