我有一个嵌套的for循环,有多个条件要使用MIPS进行转换。我的具体问题是如何从C代码中分解这一行,以便在MIPS转换中的1个分支语句中完成该指令? - >的 if((a[i] > 0) && (b[j] > 0))
*我已对代码进行了更新以分解if条件。我在火星上跑步时遇到错误。错误是:
第28行:0x00400074处的运行时异常:提取地址未在字边界上对齐0x10010069
C代码在这里:
int i, j, M, N, count;
int a[];
int b[];
for(i=0; i<M; i++) {
for(j=0; j<N; j++) {
if((a[i] > 0) && (b[j] > 0)) {
count = count + 1;
}
}
}
我所拥有的是:
.data
a: .space 100 # Declare a array with 100 bytes of data
b: .space 100 # Declare b array with 100 bytes of data
i: .word 0 # Declare i counter
j: .word # Declare j counter
.text
addi $t0, $zero, 10 # $t0 variable with score 10
addi $s1, $zero, 0 # $s1 variable with array index 0
sw $t0, a($s1) # Store 10 into a array at location
addi $t1, $zero, 15 # $t0 variable with score 15
addi $s2, $zero, 0 # $s2 variable with array index 0
sw $t1, b($s2) # Store 15 into b array at location 0
lw $t2, i($zero) # Initialize loop index i to 0
lw $t3, j($zero) # Intialize loop index j to 0
addi $s2, $zero, 5 # Initialize M to 5
addi $s3, $zero, 5 # Initialize N to 5
addi $s4, $zero, 0 # Initialize count to 0
OuterLoop: beq $t2, $s2, Exit # i=M Exit the loop
lw $t0, a($s1) # Load value from a array
bgt $t0, 0, InnerLoop # if a[i] > 0
InnerLoop: beq $t3, $s3, Exit # j=N Exit the loop
lw $t1, b($s2) # Load value from b array
bgt $t1, 0, Increment # if b[j] > 0
Increment: addi $s4, $s4, 1 # Increment count by 1
addi $t2, $t2, 1 # Increment i by 1
addi $t3, $t3, 1 # Increment j by 1
j OuterLoop
Exit:
答案 0 :(得分:1)
我认为if((a[i] > 0) && (b[j] > 0))
不能在一个分支中完成,因为当第一个操作数为真(非零)时,不能评估&&
的第二个操作数。
这是代表if((a[i] > 0) & (b[j] > 0)) count = count + 1;
(未经测试)
# assuming that i = $t2, j = $t3, count = $s4
sll $t4, $t2, 2 # calculate offset of a[i]
lw $t5, a($t4) # load a[i]
sll $t4, $t3, 2 # calculate offset of b[j]
lw $t6, b($t4) # load b[j]
slt $t4, $zero, $t5 # $t4 = (a[i] > 0)
slt $t7, $zero, $t6 # $t7 = (b[j] > 0)
and $t4, $t4, $t7 # $t4 = (a[i] > 0) & (b[j] > 0)
beq $t4, $zero, NotTrue # skip increment if the condition is false
sll $zero, $zero, 0 # nop: prevent increment from being executed when the condition is false
addi $s4, $s4, 1 # count = count + 1
NotTrue:
更新:通过更正其他错误,您的代码应如下所示:
.data
a: .space 100 # Declare a array with 100 bytes of data
bb: .space 100 # Declare b array with 100 bytes of data
.text
main:
addi $t0, $zero, 10 # $t0 variable with score 10
addi $s1, $zero, 0 # $s1 variable with array index 0
sw $t0, a($s1) # Store 10 into a array at location
addi $t1, $zero, 15 # $t0 variable with score 15
addi $s2, $zero, 0 # $s2 variable with array index 0
sw $t1, bb($s2) # Store 15 into bb array at location 0
addi $t2, $zero, 0 # Initialize loop index i to 0
addi $s2, $zero, 5 # Initialize M to 5
addi $s3, $zero, 5 # Initialize N to 5
addi $s4, $zero, 0 # Initialize count to 0
OuterLoop: beq $t2, $s2, Exit # i=M Exit the loop
addi $t3, $zero, 0 # Intialize loop index j to 0
InnerLoop: beq $t3, $s3, ExitInnerLoop # j=N Exit the loop
sll $t4, $t2, 2 # calculate offset of a[i]
lw $t5, a($t4) # load a[i]
sll $t4, $t3, 2 # calculate offset of b[j]
lw $t6, bb($t4) # load b[j]
slt $t4, $zero, $t5 # $t4 = (a[i] > 0)
slt $t7, $zero, $t6 # $t7 = (b[j] > 0)
and $t4, $t4, $t7 # $t4 = (a[i] > 0) & (b[j] > 0)
beq $t4, $zero, NoIncrement # skip increment if the condition is false
nop # prevent increment from being executed when the condition is false
addi $s4, $s4, 1 # Increment count by 1
NoIncrement:
addi $t3, $t3, 1 # Increment j by 1
j InnerLoop
nop
ExitInnerLoop:
addi $t2, $t2, 1 # Increment i by 1
j OuterLoop
nop
Exit:
# exit program
addi $v0, $zero, 10
syscall
我将标签b
更改为bb
,因为我的QtSpim抱怨使用操作码作为标签。