Question

我正在尝试格式化x轴的日期时间刻度，但我无法实现我想要的目标。

＆＃13;

var margin = {
    top: 20,
    right: 30,
    bottom: 30,
    left: 40
  },
  width = 960 - margin.left - margin.right,
  height = 500 - margin.top - margin.bottom;

var z = d3.scale.category20c();

var svg = d3.select("body").append("svg")
  .attr("width", width + margin.left + margin.right)
  .attr("height", height + margin.top + margin.bottom)
  .append("g")
  .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

var parseDate = d3.time.format("%Y-%m-%dT%H:%M:%SZ");

var data = [{
  data: [
    ["2016-01-28T15:45:26Z", 5.0],
    ["2016-01-30T15:45:26Z", 0.0],
    ["2016-02-01T15:45:26Z", 0.0],
    ["2016-02-03T15:45:26Z", 0.0],
    ["2016-02-05T15:45:26Z", 0.0],
    ["2016-02-07T15:45:26Z", 0.0],
    ["2016-02-09T15:45:26Z", 0.0],
    ["2016-02-11T15:45:26Z", 0],
    ["2016-02-13T15:45:26Z", 0],
    ["2016-02-15T15:45:26Z", 0],
    ["2016-02-17T15:45:26Z", 0],
    ["2016-02-19T15:45:26Z", 0],
    ["2016-02-21T15:45:26Z", 0],
    ["2016-02-23T15:45:26Z", 0],
    ["2016-02-25T15:45:26Z", 0]
  ],
  label: "a"
}]


var x = d3.time.scale()
  .range([0, width]);

var y = d3.scale.linear()
  .range([height, 0]);

var xAxis = d3.svg.axis()
  .scale(x)
  .orient("bottom");

var yAxis = d3.svg.axis()
  .scale(y)
  .orient("left");

var line = d3.svg.line()
  .interpolate("monotone")
  .x(function(d) {
    return x(parseDate.parse(d[0]));
  })
  .y(function(d) {
    return y(d[1]);
  });

var ary = [];
data.forEach(function(d) {
  ary.push(d.data);
});

x.domain(d3.extent(d3.merge(ary), function(d) {
  return parseDate.parse(d[0]);
}));

y.domain([
  d3.min(data, function(c) {
    return d3.min(c.data, function(v) {
      return v[1];
    });
  }),
  d3.max(data, function(c) {
    return d3.max(c.data, function(v) {
      return v[1];
    });
  })
]);

function calc(val) {
  var day = Math.floor((new Date() - val) / (24 * 60 * 60 * 1000));
  if (day === 0) {
    return 'today';
  } else {

    return '-' + day + 'D';
  }
}

xAxis.tickFormat(function(d) {
  console.log("=========");
  console.log(d);
  console.log("=========");
  return calc(d);
});
svg.append("g")
  .attr("class", "x axis")
  .attr("transform", "translate(0," + height + ")")
  .call(xAxis);

svg.append("g")
  .attr("class", "y axis")
  .call(yAxis);

var series = svg.selectAll(".series")
  .data(data)
  .enter().append("g")
  .attr("class", "series");

series.append("path")
  .attr("class", "line")
  .attr("d", function(d) {
    return line(d.data);
  })
  .style("stroke", function(d, i) {
    return z(i);
  });

＆＃13;

text.inner-circle {
  font-weight: 400;
  font-size: 12px;
  text-transform: uppercase;
}
text.inner-text {
  font-weight: 400;
  font-size: 36px;
  font-family: 'Metric Regular', 'Metric';
  text-align: center;
  font-style: normal;
  text-transform: uppercase;
}
path {
  stroke: steelblue;
  stroke-width: 2;
  fill: none;
}
.axis path,
.axis line {
  fill: none;
  stroke: grey;
  stroke-width: 2;
  shape-rendering: crispEdges;
}
.grid .tick {
  stroke: lightgrey;
  stroke-opacity: 0.7;
  shape-rendering: crispEdges;
}
.grid path {
  stroke-width: 0;
}

＆＃13;

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.11/d3.min.js"></script>

＆＃13;

当我打印x.domain()时，我的输出为[Thu Jan 28 2016 15:45:26 GMT+0530 (India Standard Time), Thu Feb 25 2016 15:45:26 GMT+0530 (India Standard Time)]，这是正确的最小值和最小值。根据具有正确时间的数据的最大值。

但是当下面提到的代码片段运行时，它并没有开始从Fri Jan 29 2016 00:00:00 GMT+0530 (India Standard Time)而不是Thu Jan 28 2016 15:45:26 GMT+0530 (India Standard Time)传递值 -

xAxis.tickFormat(function(d) {
console.log("=========");
console.log(d);
console.log("=========");
return calc(d);
});

因此，当上述代码段运行时，它会为我提供d的这些值：控制台输出

=========
Fri Jan 29 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Sun Jan 31 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Mon Feb 01 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Wed Feb 03 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Fri Feb 05 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Sun Feb 07 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Tue Feb 09 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Thu Feb 11 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Sat Feb 13 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Mon Feb 15 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Wed Feb 17 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Fri Feb 19 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Sun Feb 21 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Tue Feb 23 2016 00:00:00 GMT+0530 (India Standard Time)
=========
=========
Thu Feb 25 2016 00:00:00 GMT+0530 (India Standard Time)
=========

但是我想让代码传递输入中提到的日期时间值，而不更改它们。

请帮帮我。

Answer 1

axis的标准行为是使用具有良好圆值的规则间隔刻度。

因为你准确地知道你的蜱虫在哪里;然后axis.tickValues([values])是你的朋友。从您的数据中提取日期时间列表，并通过此功能将其提供给xAxis。

编辑：要获取您的数组值，以下行应该完成工作

myTickValues = ary[0].map(function(d){return parseDate.parse(d[0])})
xAxis.tickValues(myTickValues);

D3 x轴刻度格式＆amp;刻度值问题

1 个答案: