给出以下嵌套的JSON字符串:
string s = @"
{
""id"": 10,
""fields"":{
""issuetype"": {
""name"": ""Name of the jira item""
}
}
}";
如何使用JsonPropertyAttribute
将其反序列化为以下“扁平”类:
public class JiraIssue
{
[JsonProperty("id")]
public int Id { get; set; }
[JsonProperty("fields/issuetype/name")]
public string Type { get; set; }
}
我正在尝试将基于/
的“导航”规则指定为JSON属性名称中的分隔符。
基本上,我想指定JsonProperty("fields/issuetype/name")
应该用作嵌套属性fields.issuetype.name
的导航规则,这显然不起作用:
var d = Newtonsoft.Json.JsonConvert.DeserializeObject<JiraIssue>(s);
Console.WriteLine("Id:" + d.Id);
Console.WriteLine("Type" + d.Type);
以上仅识别Id:
Id: 10
Type:
我需要实现什么来告诉Json.NET使用“/”作为所需嵌套属性的导航路径?
答案 0 :(得分:3)
这是一种可能的方式 -
internal class ConventionBasedConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return typeof(JiraIssue).IsAssignableFrom(objectType);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
var daat = JObject.Load(reader);
var ret = new JiraIssue();
foreach (var prop in ret.GetType().GetProperties(BindingFlags.Public | BindingFlags.DeclaredOnly | BindingFlags.Instance))
{
var attr = prop.GetCustomAttributes(false).FirstOrDefault();
if (attr != null)
{
var propName = ((JsonPropertyAttribute)attr).PropertyName;
if (!string.IsNullOrWhiteSpace(propName))
{
var conventions = propName.Split('/');
if (conventions.Length == 3)
{
ret.Type = (string)((JValue)daat[conventions[0]][conventions[1]][conventions[2]]).Value;
}
ret.Id = Convert.ToInt32(((JValue)daat[propName]).Value);
}
}
}
return ret;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
}
}
var settings = new JsonSerializerSettings();
settings.Converters.Add(new ConventionBasedConverter());
var o = JsonConvert.DeserializeObject<JiraIssue>(s, settings);