我试图再添加一列作为剩余行数的列,
我不想要包含我的计划数量与完成数量匹配的行
(plan_qty!= cmp_qty)
SELECT od_f.ob_oid Order,
Sum(plan_qty) Plan_Units,
sum(cmp_qty) Completed_Units,
Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
total_value Value,
SUM(round(cmp_qty * unit_price,2)) cmp_value
FROM od_f,
om_f
WHERE od_f.ob_oid = om_f.ob_oid
GROUP BY od_f.ob_oid, total_value
ORDER BY Percent_Cmp desc
这是一个返回我想要的新列的查询
SELECT count(od_rid)
FROM od_f
WHERE od_f.plan_qty != od_f.cmp_qty
GROUP BY od_f.ob_oid
我无法添加上述where语句,因为它会影响我的结果
我真的不知道该怎么做,将这些查询组合成一个子查询?某种联盟?我迷失了怎么做。
感谢您的帮助
答案 0 :(得分:1)
您可以根据需要使用条件聚合。虽然COUNT()
CASE
可能就足够了,但我最好的猜测是COUNT(DISTINCT)
:
SELECT od_f.ob_oid Order,
Sum(plan_qty) Plan_Units,
sum(cmp_qty) Completed_Units,
Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
total_value Value,
SUM(round(cmp_qty * unit_price,2)) cmp_value,
COUNT(DISTINCT CASE WHEN od_f.plan_qty <> od_f.cmp_qty THEN od_f. od_rid END) as newcol
FROM od_f JOIN
om_f
ON od_f.ob_oid = om_f.ob_oid
GROUP BY od_f.ob_oid, total_value
ORDER BY Percent_Cmp desc;
您还应该学会使用正确的,明确的JOIN
语法。简单的规则:从不在FROM
子句中使用逗号。
答案 1 :(得分:1)
@GordonLinoff解决方案对您有好处,但只有当您想要计算唯一的od_rid时,此解决方案适用于这两种情况,使用相关查询:
SELECT t.ob_oid Order,
Sum(plan_qty) Plan_Units,
sum(cmp_qty) Completed_Units,
Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
total_value Value,
SUM(round(cmp_qty * unit_price,2)) cmp_value,
(SELECT count(f2.od_rid) FROM od_f f2
WHERE f2.plan_qty != f2.cmp_qty and f2.ob_oid = f.ob_oid) as newcolumn
FROM od_f t
INNER JOIN om_f
ON t.ob_oid = om_f.ob_oid
GROUP BY t.ob_oid, total_value
ORDER BY Percent_Cmp desc
答案 2 :(得分:0)
根据我的理解,您只需要plan_qty
不等于cmp_qty
的行数,请尝试以下操作:
SELECT t.ob_oid AS order,
SUM(plan_qty) AS plan_units,
SUM(cmp_qty) AS completed_units,
ROUND(((SUM(cmp_qty)/SUM(plan_qty)) * 100),2) AS percent_cmp,
total_value AS value,
SUM(ROUND(cmp_qty * unit_price,2)) AS cmp_value,
SUM(DECODE(plan_qty, cmp_qty, 0, 1)) AS rows_left
FROM od_f t
INNER JOIN om_f
ON t.ob_oid = om_f.ob_oid
GROUP BY t.ob_oid, total_value
ORDER BY percent_cmp DESC;