Question

当我想出这个问题时，我一直在测试我的班级。我尝试了一切，但似乎我找不到任何解决方案。这是我的pseudo code:

String[] pastaRecipe = {a, b, c, d, e};
String[] saladRecipe = {f, g, h, i, j};
String[][] finalRecipes = {pastaRecipe, saladRecipe};

String[] testInput = {a, b, c, d, e};

    if (pastaRecipe contansAll testInput) then
        print You coulds cook a pasta
    end

这是我的实施：

public class RecipeTest() {
    public static void main(String[] args) {

        try {

            ArrayList<String> results = new ArrayList<>();

            String[] porkSteak = {"Pork", "Garlic", "Dried bay leaves", "Vinegar", "Soy sauce", "Whole pepper corn", "Salt"};
            String[] porkSoup = {"Pork", "String Beans", "Vinegar", "Soy sauce", "Whole pepper corn", "salt"};
            String[][] finalRecipes = {porkSteak, porkSoup};


            String[] testInput = {"Pork", "Garlic", "Dried bay leaves", "Vinegar", "Soy sauce", "Whole pepper corn", "Salt"};

            for (int i = 0; i < finalRecipes.length; i++) {

                if(Arrays.asList(testInput).containsAll(Arrays.asList(finalRecipes[i]))) {

                    results.add(finalRecipes[i][finalRecipes.length - 1]);

                }
            }

            System.out.println("You can cook " + results.get(0));

    }
}

我的输出：           你可以煮盐

预期产量：           你可以煮猪肉。

Answer 1

要使其工作量最少，您必须创建一个配方名称数组，并使其与finalRecipes数组保持同步。 E.g。

String[][] finalRecipes = {porkSteak, porkSoup};
String[] recipeNames = {"Pork Steak", "Pork Soup"};

然后在if

中使用它

if (Arrays.asList(testInput).containsAll(Arrays.asList(finalRecipes[i]))) {
    results.add(recipeNames[i]);
}

但理想情况下，您希望创建一个Recipe类，其中包含成分列表及其名称。

Java containsAll从多维数组中返回错误的索引

1 个答案: