Question

我有两个名为'Students_tbl'和'admission'的表。我想同时在两个表中插入入场号，这样在'students_tbl'中，它是一个外键，而在'permit'表中，它是一个主键。 'students_tbl'的主键是“std_index” 我正在使用一个HTML表单。我写的代码输出错误。感谢您提前回复

以下是代码

<?php

$manzu =mysqli_connect("localhost","root","MANZu1992", "cdms");

// Check connection
if (!$manzu) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    echo "Please Check your connection. We were unable to connect you to the desired site.";
}

if (isset($_POST['submit'])) {
    $identification = mysqli_real_escape_string($manzu, $_POST['iddd']);
    $National_Number = mysqli_real_escape_string($manzu, $_POST['national_Numberr];


    $sql = "INSERT INTO students_tbl (std_index,std_national_number) 
    VALUES ('$identification','$National_Number')";

    $sql = "INSERT INTO admission (Admission_Number)VALUES($National_Number)";

    if (!mysqli_query($manzu,$sql)) {
        die('Error: ' . mysqli_error($manzu));
    }ELSE {
        die ('Thank you for registering');
    }
}

?>

Answer 1

您缺少结束括号并引用

在覆盖$sql

之前，您没有执行第一个查询

<?php    
$manzu =mysqli_connect("localhost","root","MANZu1992", "cdms");
if (!$manzu) {
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    echo "Please Check your connection. We were unable to connect you to the desired site.";
}    
if (isset($_POST['submit'])) {
    $identification = mysqli_real_escape_string($manzu, $_POST['iddd']);
    $National_Number = mysqli_real_escape_string($manzu, $_POST['national_Numberr']);
    $sql = "INSERT INTO students_tbl (std_index,std_national_number)  VALUES ('$identification','$National_Number')";
    mysqli_query($manzu,$sql);
    $sql = "INSERT INTO admission (Admission_Number)VALUES($National_Number)";  
    if (!mysqli_query($manzu,$sql)) {
        die('Error: ' . mysqli_error($manzu));
    }else {
        die ('Thank you for registering');
    }
}
?>

使用mysql和php将数据插入两个mysql表

1 个答案: