Question

我需要编写一个打开两个文件的函数，如果某个比较为真，则将结果写入第三个文件：

def crack_pass_file(pass_filename,words_filename,out_filename):
    f1=open(pass_filename)
    f2=open(words_filename)
    f3=open(out_filename,'w')
    for line1 in f1:
        x=make_dictionary(line1.split(":"))
        password=x["password"]
        name=x["account"]
        for line2 in f2:
            if (check_pass(line2.strip(),password)==True):
                f3.write(name + "="+line2.strip())

文件f1是一个包含以下内容的文件：

root:VgzdTLne0kfs6:0:0:Corema Latterll:/home/root:/bin/bash
checani:IqAFDoIjL2cDs:1:1:Pengpu Checani:/home/checani:/bin/bash
rkrakow:DLD3nJmCvt3pY:2:2:Rodentia Krakow:/home/rkrakow:/bin/bash
forkland:oWMVyy1FTdNL6:3:3:Forkland Maskins:/home/forkland:/bin/bash
obongo:O44lPEloqk5tY:4:4:Obongo Obwalden:/home/obongo:/bin/bash
pglenda:xboW5dHcsqvSQ:5:5:Pahsien Glenda:/home/pglenda:/bin/bash
madel:qEHvJXMkTSAZA:6:6:Madel Aporosa:/home/madel:/bin/bash
ssauks:Q3Kz1z7eAiwjg:7:7:Schober Sauks:/home/ssauks:/bin/bash
slajoie:wWTHgoE8SC8W6:8:8:Scheiner Lajoie:/home/slajoie:/bin/bash
tieton:RWORYLxRSSzMU:9:9:Lerwa Tieton:/home/tieton:/bin/bash

其中每一行都有一个用户，一个密码和一堆其他东西。对于第1行，root是用户，VgzdTLne0kfs6是加密密码。每隔一行使用相同的格式。我需要做的是获取加密密码，看看是否在另一个文件f2中使用密码调用crypt，其中包含按字母顺序排列的巨大单词列表，如：

embordering
emborders
emboscata
embosk
embosked
embosking

将该密码设为加密密码。我已经有了这样做的功能，它可以工作：

def check_pass(plain,enc):
    s = enc[0:2]
    x = crypt.crypt(plain, s)
    if x==enc: return True
    else: return False

这里也是makedictionary函数，我用来从文件1的每一行创建一个字典，也工作我已经测试过了：

def make_dictionary(s):
    d={}
    d["account"]=s[0]
    d["shell"]=s[6]
    d["UID"]=int(s[2])
    d["GID"]=int(s[3])
    d["GECOS"]=s[4]
    d["directory"]=s[5]
    d["password"]=s[1]
    return d

当我测试它时，它写道：根= stroam 输出文件，这是第一个用户的解密密码，但没有写任何其余的。这应该是结果：

root=stroam
checani=asarta
rkrakow=sinklike
obongo=yawnful
madel=aviatic
tieton=dagesh
pglenda=sngissa
forkland=relliarb
slajoie=mu2j1k
ssauks=EGaFeIHC

我在单词文件中找到了所有这些单词（yawnful，aviatic等）但由于某种原因它们没有被匹配。我也尝试过这样做： check_pass（＆＃34; asarta＆＃34;，＆＃34; IqAFDoIjL2cDs＆＃34;）和其他一些他们都返回true所以我很困惑为什么他们中的更多不打印到我的输出文件。

Answer 1

您希望评估f1中f2中每一行的f2中的每一行。但是，在f1的第一次迭代中，您会使用f2中的每一行。在第二次迭代中，for line1 in f1: # ... for line2 in f2:为空，您将不会进入此循环的主体。

for line in f1

相反，在f2_lines = [line2 for line2 in f2] ... for line1 in f1:循环之外，生成f2（以及可选f1）中的行列表，如下所示：

for line2 in f2_lines:

现在你可以使用

f1

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Answer 2

第一次迭代f2时，你耗尽了迭代器，而f2的所有未来迭代都是根本不执行的循环。将f2的所有行加载到list中，以便可以多次迭代，或者在耗尽后调用f2.seek(0)以重置文件指针。

python迭代并写入文件

2 个答案: