Question

说我有这个功能：

function run_sanity_check(){
   echo -e "This is test level 1\n"
   echo -e "This is test level 2\n"
}

和另一个功能：

function run_test(){
  ... environment setup routine runs here
  echo -e "Running tests...\n"

  run_sanity_check --> this would be my call for the function above
}

当我打电话给＆＃34; run_test＆＃34;我收到此错误：功能：未找到

感谢任何帮助。

Answer 1

正如Brian的评论所提到的，您需要使用function或()，而不是两者都使用。

以下两项均有效，基于the documentation。

function run_sanity_check{
   echo -e "This is test level 1\n"
   echo -e "This is test level 2\n"
}


run_sanity_check(){
   echo -e "This is test level 1\n"
   echo -e "This is test level 2\n"
}

以下脚本打印预期输出。

run_sanity_check(){
   echo -e "This is test level 1\n"
   echo -e "This is test level 2\n"
}

run_test(){
  echo -e "Running tests...\n"

  run_sanity_check 
}

run_test

如何在Shell脚本中调用另一个函数中的函数？

1 个答案: