Python：在for循环中打印两个列表

Question

我有两个清单。

one=["first","second"]
two=[1,2]
for o in one:
    for t in two:
        print(o)
        print(t)

，输出为：

first
1
first
2
second
1
second
2

以下是正确的输出：

first
1
2
second
1
2

还有一位，我的教授要求打印输出 -

first
1
second
2

Answer 1

我认为这就是你想要的：

for o in one:
    print(o)
    for t in two:
        print(t)

因此，每次运行内循环时，只打印一次字符串数。

编辑：

你可以这样做：

both = zip(one, two)
for tup in both:
  for val in tup:
    print(val, end=' ')

Answer 2

for o in one:
    print(o)
    for t in two:
        print(t)

Answer 3

稍微改变一下。

    one=["first","second"]
    two=[1,2]
    for o in one:
        print(o)
        for t in two:
            print(t)

Answer 4

您的代码应为：

one=["first","second"]
two=[1,2]
for o in one:
    print(o)
    for t in two:
        print(t)