Question

我正在使用jquery发送包含这样的元素数组的json数据

$('#brand_category').click(function(event){

        category = $("input:checkbox[name=category]:checked").map(function() {
        return this.value;
        }).get();

        brand = $("input[type='radio']:checked").map(function() {
        return this.value;
        }).get();

        parameter.push({
          brand :   brand,
          category: category
        });

        var json = JSON.stringify(parameter)

        $.ajax({
            type: 'post',
            url: "{% url 'seller_details' %}",
            data: {'parameter[]' : json , csrfmiddlewaretoken:'{{csrf_token}}'},
            success: function(data){
            },
            error:function (response, error){
            }
            });

在视图中我正在收集像这样的数据

brand_category = self.request.POST.get('parameter[]')
print brand_category

这将打印数据

[{"brand":["spykar"],"category":["Women Clothing","Dresses"]},{"brand":["Madame"],"category":["Women Clothing","Dresses"]}]

然后我试图像这样循环json

for list in list_data:
                brand =  list_data['brand']
                print brand
                categories = list_data['category']
                print categories

但是我收到了错误

list indices must be integers, not str

如何循环浏览json数据以获取品牌和类别列表？

Answer 1

您的外部循环是一个列表，然后循环遍历列表中的每个字典。此外，您必须将字符串转换为python对象。

import json
brand_category = self.request.POST.get('parameter[]')
Lbrand_category = json.loads(brand_category)
for D in Lbrand_category:
   brand,categories = D['brand'],D['category']

注意：如果您只想要没有列表的品牌字符串，请使用：

brand,categories = D['brand'][0],D['category']

Answer 2

我推荐你这个AJAX请求（更清楚）：

$('#brand_category').click( sendAjax );

function sendAjax()
{
  var category = $("input:checkbox[name='category']:checked").val();
  var brand = $("input[type='radio']:checked").val();

  var data = { "category" : category, "brand" : brand, "csrfmiddlewaretoken" : '{{csrf_token}}' }

  $.ajax({
    type: 'post',
    url: "{% url 'seller_details' %}",
    data: data,
    success: function(data)
    {
      //console.log(data) // Print the response of Django or see this in "Network" request, F12 Chrome
    },
    error:function (response, error)
    {
    }
  });
}

查看：

category = request.POST['category']
print category

brand    = request.POST['brand']
print brand

在JavaScript中列出品牌数据：

var data = {} //This is a empty object named data
data.brans = [];

然后你需要创建一个选择所有品牌

for ("list of brands"){
  brand_name = logic
  data.brands.push(brand_name)
} //This is only a idea

如何使用jquery在django中获取json数据

2 个答案: