我正在使用jquery发送包含这样的元素数组的json数据
$('#brand_category').click(function(event){
category = $("input:checkbox[name=category]:checked").map(function() {
return this.value;
}).get();
brand = $("input[type='radio']:checked").map(function() {
return this.value;
}).get();
parameter.push({
brand : brand,
category: category
});
var json = JSON.stringify(parameter)
$.ajax({
type: 'post',
url: "{% url 'seller_details' %}",
data: {'parameter[]' : json , csrfmiddlewaretoken:'{{csrf_token}}'},
success: function(data){
},
error:function (response, error){
}
});
在视图中我正在收集像这样的数据
brand_category = self.request.POST.get('parameter[]')
print brand_category
这将打印数据
[{"brand":["spykar"],"category":["Women Clothing","Dresses"]},{"brand":["Madame"],"category":["Women Clothing","Dresses"]}]
然后我试图像这样循环json
for list in list_data:
brand = list_data['brand']
print brand
categories = list_data['category']
print categories
但是我收到了错误
list indices must be integers, not str
如何循环浏览json数据以获取品牌和类别列表?
答案 0 :(得分:2)
您的外部循环是一个列表,然后循环遍历列表中的每个字典。此外,您必须将字符串转换为python对象。
import json
brand_category = self.request.POST.get('parameter[]')
Lbrand_category = json.loads(brand_category)
for D in Lbrand_category:
brand,categories = D['brand'],D['category']
注意:如果您只想要没有列表的品牌字符串,请使用:
brand,categories = D['brand'][0],D['category']
答案 1 :(得分:0)
我推荐你这个AJAX请求(更清楚):
$('#brand_category').click( sendAjax );
function sendAjax()
{
var category = $("input:checkbox[name='category']:checked").val();
var brand = $("input[type='radio']:checked").val();
var data = { "category" : category, "brand" : brand, "csrfmiddlewaretoken" : '{{csrf_token}}' }
$.ajax({
type: 'post',
url: "{% url 'seller_details' %}",
data: data,
success: function(data)
{
//console.log(data) // Print the response of Django or see this in "Network" request, F12 Chrome
},
error:function (response, error)
{
}
});
}
查看:
category = request.POST['category']
print category
brand = request.POST['brand']
print brand
在JavaScript中列出品牌数据:
var data = {} //This is a empty object named data
data.brans = [];
然后你需要创建一个选择所有品牌
for ("list of brands"){
brand_name = logic
data.brands.push(brand_name)
} //This is only a idea