Question

我有这个MongoDB架构Buzzer

    {
    "_id": {
        "$oid": "56cd9c103ff0020300fa1135"
    },
    "title": "50x kliky",
    "timing": "2x týdně",
    "user": "Stejk",
    "history": [
        {
            "title": "50x kliky",
            "datum": "11.09.2016",
            "done": false
        },
        {
            "title": "50x kliky",
            "datum": "11.09.2016",
            "done": true
        },
        {
            "title": "50x kliky",
            "datum": "11.09.2016",
            "done": true
        },
        {
            "title": "50x kliky",
            "datum": "11.09.2016",
            "done": true
        },
        {
            "title": "50x kliky",
            "datum": "11.09.2016",
            "done": true
        }
    ],
    "__v": 0
}

我希望得到完成的数组。怎么做，我完全失去了。我现在不知道如何让它发生。请帮助。

非常感谢您的帮助

Answer 1

请尝试通过以下aggregation进行操作。

 Buzzer.aggregate([
    // unwind the history array
    {$unwind: '$history'},
    // filter the done field is true document
    {$match: {'history.done': true}},
    // count the result
    {$group: {_id: '$_id', count: {$sum: 1}}}
 ], function(err, doc) {

 });

Answer 2

在普通的Javascript中，您可以使用Array#reduce：

var data = { "_id": { "$oid": "56cd9c103ff0020300fa1135" }, "title": "50x kliky", "timing": "2x týdne", "user": "Stejk", "history": [{ "title": "50x kliky", "datum": "11.09.2016", "done": false }, { "title": "50x kliky", "datum": "11.09.2016", "done": true }, { "title": "50x kliky", "datum": "11.09.2016", "done": true }, { "title": "50x kliky", "datum": "11.09.2016", "done": true }, { "title": "50x kliky", "datum": "11.09.2016", "done": true }], "__v": 0 },
    count = data.history.reduce(function (r, a) {
        return r + a.done;
    }, 0);

document.write(count);

Answer 3

还有另外一个问题。怎么做到这一点。（看评论）

    BuzzerListekSchema.statics.getBuzzerListekDetailPercentage = function(req, response, res){
  // Function1
  this.aggregate([
    {$unwind: '$history'},
    {$match: {'history.done': true}}, //Filtr
    {$group: {_id: req.params.id, count: {$sum: 1}}}
 ], function(err, c){
   if(err){
     res.status(500).json({succes: false, msg: 'Error'});
   }
   else {
    // Here is result c
    // {_id: ubuiabiufbuiab, count: 5}
   }
 });

 // Function2
 this.aggregate([
   {$unwind: '$history'},
   {$group: {_id: req.params.id, count: {$sum: 1}}}
], function(err, c){
  if(err){
    res.status(500).json({succes: false, msg: 'Error'});
  }
  else {
    // Here is result c
    // {_id: ubuiabiufbuiab, count: 5}
  }
});
  //Here i want reach a percent of percent=Function1/(Function2/100) and send it by JSON
  //res.json({succes: false, msg: percent});

};

嵌套数组的数量

3 个答案: