添加从Entity，Symfony中的连接表字段中选择

Question

当我跑步时：

{
  "rules": {
    "updates": {
      "$location_id": { // $location_id should act like a wild card
        ".indexOn": ["validFrom"]
      }
    }
  }
}

它产生以下结构：

$this->createQueryBuilder('debtor')
->join('debtor.deals', 'deal')
->addSelect('...something... as closed_deals_count')
->getQuery()
->getSingleResult()

我怎么能用＆＃39; closed_deals_count＆＃39;来获得单一的债务人记录？在它而不是数组？

Answer 1

我认为你正在寻找getSingleScalarResult。类似的东西：

$this->createQueryBuilder('debtor')
->join('debtor.deals', 'deal')
->addSelect('COUNT(deal.id) as closed_deals_count')
->getQuery()
->getSingleScalarResult()