Question

如何将IEnumerable转换为ObservableCollection？

Answer 1

根据MSDN

var myObservableCollection = new ObservableCollection<YourType>(myIEnumerable);

这将生成当前IEnumerable的浅表副本并将其转换为ObservableCollection。

Answer 2

如果你正在使用非通用IEnumerable，你可以这样做：

public ObservableCollection<object> Convert(IEnumerable original)
{
    return new ObservableCollection<object>(original.Cast<object>());
}

如果你正在使用通用IEnumerable<T>，你可以这样做：

public ObservableCollection<T> Convert<T>(IEnumerable<T> original)
{
    return new ObservableCollection<T>(original);
}

如果你正在使用非通用IEnumerable但知道元素的类型，你可以这样做：

public ObservableCollection<T> Convert<T>(IEnumerable original)
{
    return new ObservableCollection<T>(original.Cast<T>());
}

Answer 3

为了使事情变得更加简单，您可以创建一个Extension方法。

public static class Extensions
{
    public static ObservableCollection<T> ToObservableCollection<T>(this IEnumerable<T> col)
    {
        return new ObservableCollection<T>(col);
    }
}

然后你可以在每个IEnumerable

上调用该方法

var lst = new List<object>().ToObservableCollection();

Answer 4

ObservableCollection<decimal> distinctPkgIdList = new ObservableCollection<decimal>();
guPackgIds.Distinct().ToList().ForEach(i => distinctPkgIdList.Add(i));

// distinctPkgIdList - ObservableCollection
// guPackgIds.Distinct() - IEnumerable

Answer 5

将IEnumerable转换为ObservableCollection的C＃函数

private ObservableCollection<dynamic> IEnumeratorToObservableCollection(IEnumerable source)
    {

        ObservableCollection<dynamic> SourceCollection = new ObservableCollection<dynamic>();

        IEnumerator enumItem = source.GetEnumerator();
        var gType = source.GetType();
        string collectionFullName = gType.FullName;
        Type[] genericTypes = gType.GetGenericArguments();
        string className = genericTypes[0].Name;
        string classFullName = genericTypes[0].FullName;
        string assName = (classFullName.Split('.'))[0];

        // Get the type contained in the name string
        Type type = Type.GetType(classFullName, true);

        // create an instance of that type
        object instance = Activator.CreateInstance(type);
        List<PropertyInfo> oProperty = instance.GetType().GetProperties().ToList();
        while (enumItem.MoveNext())
        {

            Object instanceInner = Activator.CreateInstance(type);
            var x = enumItem.Current;

            foreach (var item in oProperty)
            {
                if (x.GetType().GetProperty(item.Name) != null)
                {
                    var propertyValue = x.GetType().GetProperty(item.Name).GetValue(x, null);
                    if (propertyValue != null)
                    {
                        PropertyInfo prop = type.GetProperty(item.Name);
                        prop.SetValue(instanceInner, propertyValue, null);
                    }
                }
            }

            SourceCollection.Add(instanceInner);
        }

        return SourceCollection;
    }

如何将IEnumerable转换为ObservableCollection？

5 个答案: