如何获取跟随JSON的C＃对象

Question

我有这种JSON，如何用newtonsoft转换为C＃对象。

[["Newyork", "Goods & Services", "Description", "02/23/2016", "03/15/2016", "some info"]]

Answer 1

使用以下代码：

string jsonString = @"[[""Newyork"", ""Goods & Services"", ""Description"", ""02/23/2016"", ""03/15/2016"", ""some info""]]";

List<string[]> data = JsonConvert.DeserializeObject<List<string[]>>(jsonString);

Answer 2

您可以使用JsonConvert.DeserializeObject进行此转换。如下所示：

string inputString= @"[[""Newyork"", ""Goods & Services"", ""Description"", ""02/23/2016"", ""03/15/2016"", ""some info""]]";    
List<string[]> jsonData = JsonConvert.DeserializeObject<List<string[]>>(inputString);