Question

我有一个赌博网站的脚本。

我需要的是，在2次调用函数multiply之后，它会调用可能的最大赌注，然后调用函数reset，我的意思是在每两次连续丢失中它会完全平衡在我的帐户重置最低赌注并继续玩，因为我意识到在手动下注的情况下赔率为1.1。在每2次失败中，下一次将获胜。

就像：2次乘法后，全部余额（下图中的＆＃34; MAX＆＃34;按钮）下注并重置游戏继续播放。我清楚了吗？

我试图为此创建一个函数但是没有用

＆＃34;最大赌注＆＃34;按钮元素代码是：

<a href="javascript:void(0);" id="double_your_btc_max" style="color: inherit;">MAX</a>

this is the printscreen

我要修改的脚本部分就是这个，已经创建了multiplyCalls函数。我将var multiply = (current * 2).toFixed(8);更改为var multiply = (current * 1).toFixed(8);，因为我的策略没有鞅。

function multiply(){
        if(multiplyCalls < 2){ // test multiply
            var current = $('#double_your_btc_stake').val();
            var multiply = (current * 2).toFixed(8);
            $('#double_your_btc_stake').val(multiply);
            multiplyCalls++; // increment
        }else{
            reset();
            console.log('=== RESETING ===');
        }
}

这是完整的脚本：

var startValue = '0.00000001', // Don't lower the decimal point more than 4x of current balance
        stopPercentage = 0.001, // In %. I wouldn't recommend going past 0.08
        maxWait = 500, // In milliseconds
        stopped = false,
        stopBefore = 3; // In minutes
        multiplyCalls = 0; // <--- Added this global

var $loButton = $('#double_your_btc_bet_lo_button'),
                $hiButton = $('#double_your_btc_bet_hi_button');


function multiply(){
        if(multiplyCalls < 2){ // test multiply
            var current = $('#double_your_btc_stake').val();
            var multiply = (current * 1).toFixed(8);
            $('#double_your_btc_stake').val(multiply);
            multiplyCalls++; // increment
        }else{
            reset();
            console.log('=== RESETING ===');
        }
}

function getRandomWait(){
        var wait = Math.floor(Math.random() * maxWait ) + 100;

        console.log('Waiting for ' + wait + 'ms before next bet.');

        return wait ;
}

function startGame(){
        console.log('Game started!');
        reset();
        $loButton.trigger('click');
}

function stopGame(){
        console.log('Game will stop soon! Let me finish.');
        stopped = true;
}

function reset(){
        $('#double_your_btc_stake').val(startValue);

}

// quick and dirty hack if you have very little bitcoins like 0.0000001
function deexponentize(number){
        return number * 1000000;
}

function iHaveEnoughMoni(){
        var balance = deexponentize(parseFloat($('#balance').text()));
        var current = deexponentize($('#double_your_btc_stake').val());

        return ((balance*2)/100) * (current*2) > stopPercentage/100;
}

function stopBeforeRedirect(){
        var minutes = parseInt($('title').text());

        if( minutes < stopBefore )
        {
                console.log('Approaching redirect! Stop the game so we don\'t get redirected while loosing.');
                stopGame();

                return true;
        }

        return false;
}

// Unbind old shit
$('#double_your_btc_bet_lose').unbind();
$('#double_your_btc_bet_win').unbind();

// Loser
$('#double_your_btc_bet_lose').bind("DOMSubtreeModified",function(event){
        if( $(event.currentTarget).is(':contains("lose")') )
        {
                console.log('You LOST! Multiplying your bet and betting again.');

                multiply();

                setTimeout(function(){
                        $loButton.trigger('click');
                }, getRandomWait());

                //$loButton.trigger('click');
        }
});

// Winner
$('#double_your_btc_bet_win').bind("DOMSubtreeModified",function(event){
        if( $(event.currentTarget).is(':contains("win")') )
        {
                if( stopBeforeRedirect() )
                {
                        return;
                }

                if( iHaveEnoughMoni() )
                {
                        console.log('You WON! But don\'t be greedy. Restarting!');

                        reset();

                        if( stopped )
                        {
                                stopped = false;
                                return false;
                        }
                }
                else
                {
                        console.log('You WON! Betting again');
                }

                setTimeout(function(){
                        $loButton.trigger('click');
                }, getRandomWait());
                multiplyCalls = 0; // reset value
        }
});startGame

Answer 1

所以基本上，你希望在两次失利后最大化赌注。因为乘法调用仅在丢失之后发生，所以我们可以假设if(multiplyCalls < 2)位处理它。因此，在以下else中，您真正需要做的就是点击最大赌注而不是调用reset()。根据我对代码的理解，这应该足够了，对吗？

function multiply(){
    if(multiplyCalls < 2){ // test multiply
        var current = $('#double_your_btc_stake').val();
        var multiply = (current * 1).toFixed(8);
        $('#double_your_btc_stake').val(multiply);
        multiplyCalls++; // increment
    }else{
        //reset(); /* instead of resetting here, let's max the bet. */
        $('#double_your_btc_max').trigger('click');
        console.log('=== RESETING ===');
    }
}

我需要一个赌博脚本的解决方案

1 个答案: