Question

我有这张桌子

noArticle QuantiteCommandee    

10        20
20         9
40         4
50         2
60
70         8
80
81
90         1
95         3

我想要计算有多少文章在量化中的数量超过5且少于2

我现在拥有的：

/
SELECT COUNT ( case when QuantiteCommandee > 5 THEN 1 ELSE 0 END) AS PLUSQUE5,     
COUNT ( case when QuantiteCommandee < 2 THEN 1 ELSE 0 END ) AS PLUSPETITQUE2
From (SELECT Article.noArticle, SUM (quantite) AS QuantiteCommandee
FROM  Article
LEFT JOIN LigneCommande ON Article.noArticle = LigneCommande.noArticle
GROUP By ( Article.noArticle))
/

它让我回头

 PLUSQUE2 PLUSQUE5
10    10

它似乎看不到我的状况＆gt; 5和＆lt; 2

编辑：从表中你看到的是顶部的表格我不知道我能给你的信息是什么？

已解决：删除ELSE PART

Answer 1

请试试这个 -

SELECT
        COUNT ( case when QuantiteCommandee > 5 THEN 1 END)  AS PLUSQUE5,     
        COUNT ( case when QuantiteCommandee < 2 THEN 1 END ) AS PLUSPETITQUE2
    From    (
                SELECT
                        Article.noArticle, SUM (quantite) AS QuantiteCommandee
                    FROM  Article
                    LEFT JOIN LigneCommande ON Article.noArticle = LigneCommande.noArticle
                GROUP By (Article.noArticle)
            )

Answer 2

使用此查询

select count(case when QuantiteCommandee>5 then 1 end) count_greaterthan_5,
count(case when QuantiteCommandee<2 then 1 end) count_lessthan_2 
from sandeep24feb_3;

COUNT（）有一些条件

2 个答案: