我终于弄清楚是什么让我称之为'文件夹'的元素打开和关闭。问题是,当我通过validator运行HTML文档时,此时<isfolder="true">
元素上不允许使用属性div
。
<p></p>
<div class="folderOpenClose" onclick="toggleAllFolders();">Open/Close Folders</div>
<p></p>
<div class="folderlabel" onclick="togglefolder('folder0');">Dice Roller</div>
<div id="folder0" class="folder" isfolder="true" style="display: none;">
</div>
<p></p>
<div class="folderlabel" onclick="togglefolder('folder1');">Slide Show</div>
<div id="folder1" class="folder" isfolder="true" style="display: none;">
</div>
<p></p>
<div class="folderlabel" onclick="togglefolder('folder2');">Carousel</div>
<div id="folder2" class="folder" isfolder="true" style="display: none;">
</div>
<p></p>
<div class="folderlabel" onclick="togglefolder('folder3');">Menu Bar</div>
<div id="folder3" class="folder" isfolder="true" style="display: none;">
</div>
<p></p>
我删除的问题是操作Open / Close All的问题,当我尝试将代码放在表单中时,Open / Close文件夹不起作用。
var lastChecked = null;
function togglefolder(id){
var ele = object(id);
if(ele.style.display == 'none') ele.style.display='block';
else ele.style.display = 'none';
}
function setAllFolders(how){
var way = ""+how;
if(way == "") way = "none";
if(way == "closed") way = "none";
if(way == "open") way = "block";
var divs = window.document.getElementsByTagName('div');
for(var i=0; i < divs.length; i++){
if(divs[i].getAttribute('data-isfolder')&&divs[i].getAttribute('data-isfolder')=='true')
divs[i].style.display = way;
var thisClass = ""+divs[i].getAttribute('class');
if(thisClass=='folderlabel'){
var thelabel = ""+divs[i].innerHTML;
if(thelabel.indexOf('open/close all folders') != -1)
divs[i].setAttribute('class','folderlabelopen');
}
}
last_toggle=way;
}
答案 0 :(得分:1)
<div id="folder2" class="folder" isfolder="true" style="display: none;"></div>
isfolder
不是已知的HTML属性,因此会被标记。
一种解决方案是使用data-*
属性,例如:
<div id="folder2" class="folder" data-isfolder="true" style="display: none;"></div>
然后您的代码可以使用:
if(divs[i].getAttribute('data-isfolder') == 'true')
您还可以使用漂亮的dataset API。