我有一张桌子:
ID | rows | dimensions
---+------+-----------
1 | 1 | 15 x 20
2 | 3 | 2 x 10
3 | 5 | 23 x 33
3 | 7 | 15 x 23
4 | 2 | 12 x 32
我希望有类似的东西:
ID | rows | dimensions
---+------+-----------
1 | 1 | 15 x 20
2 | 3 | 2 x 10
3a | 5 | 23 x 33
3b | 7 | 15 x 23
4 | 2 | 12 x 32
如何找到多重ID值以使其唯一?
如何在?
之后更新父表感谢您的帮助!
答案 0 :(得分:1)
with stats as (
SELECT "ID",
"rows",
row_number() over (partition by "ID" order by rows) as rn,
count(*) over (partition by "ID") as cnt
FROM Table1
)
UPDATE Table1
SET "ID" = CASE WHEN s.cnt > 1 THEN s."ID" || '-' || s.rn
ELSE s."ID"
END
FROM stats s
WHERE S."ID" = Table1."ID"
AND S."rows" = Table1."rows"
我假设你不能拥有两行同样
ID
和rows
的其他行,你需要在"dimensions"
包含WHERE
。
在这种情况下输出为