Question

我是python语言的新手只是想要一个python程序的帮助，我在很多热门和试用之后设法写了。

from time import sleep
from Tkinter import *

def qf(par):
    print(par)
class App:
    def __init_(self, master):
        frame = Frame(self, master)
        frame.pack()
        self.button = Button(frame, text='LED ON', command=self.convert0)
        self.button.grid(row=5, coloumnspan=5)
    def convert0(self, tog[0]):
        tog[0] = not tog[0]
        if tog[0]:
            self.button.config(text='LED OFF')
        else:
            self.button.config(text='LED OFF'. command=lambda:qf("1!!!"))
root = Tk()
root.wm_title('LED Prog')
app = App(root)
root.mainloop()

程序的输出是当我点击“LED开启”按钮时。它超越了价值＆＃39; 1 !!!＆＃39;按钮卡在＆＃39; LED ON＆＃39;，不会更改为＆＃39; LED OFF＆＃39;。

我想要的是按钮是＆＃39; LED ON＆＃39;那个时间1 !!!!应该显示在输出中，当按钮是“LED关闭”时不应显示任何值。

我知道这可能是python专家的一个小代码更改，但在这里需要一些帮助。任何人都可以分享一些学习python的链接。

提前致谢。请不要阻止这个问题我正在使用python 2.7.9

Answer 1

使用button.configure(text=)更改文字，在OFF和ON之间切换，使用变量保存状态。

from time import sleep
from Tkinter import *


class App:
    def __init__(self, master):
        frame = Frame(master)
        frame.pack()
        self.button = Button(frame, text='LED ON', command=self.convert0)
        self.button.pack()
        self.state = 1

    def convert0(self):
        states = ['ON', 'OFF']
        self.state = not self.state
        # True == 1 and False == 0
        self.button.configure(text='LED {0}'.format(states[not self.state]))

root = Tk()
root.wm_title('LED Prog')
app = App(root)
root.mainloop()

使用grid方法：

grid(row=, column=) then you can give `rowspan` or `columnspan`.

Answer 2

如果我理解你的话，那就是你要找的东西：

from Tkinter import *

class App:
    def __init__(self, master):
        """ The constructor consists of a a root widget to which
        is attached one Button child widget.
        """
        frame = Frame(master)
        frame.pack()
        self.led = Button(frame, fg="red", text="Start",  width=15,command=self.button_state)
        self.led.pack() # Use pack() if no other widgets are planned to take place
    def button_state(self):
        """ Switch the button text from LED OFF to LED ON: 1
        At the start of the program, the button text is set to 'Start'.
        """
        if self.led["text"] == "LED OFF" or self.led["text"] == "Start":
            self.led["text"] ="LED ON: 1"
        else:
            self.led["text"]="LED OFF"


root = Tk()
root.wm_title('LED Prog')
app = App(root)
root.mainloop()

<强>结果：

单击按钮将在以下两种状态之间切换：

Answer 3

终于得到了我所寻求的希望，这也有助于其他人。

from time import sleep
from Tkinter import *

class App:

def __init__(self, master): 
        frame = Frame(master)
        frame.pack()

        self.button = Button(frame, text='LED ON', command=self.convert0)
        self.button.grid(row=2, column=0)

        self.LED = Label(frame).grid(row=2, column=1)

def convert0(self, tog=[0]):

    tog[0] = not tog[0]
    if tog[0]:
        print('1')
        self.button.config(text='LED OFF')
    else:
        self.button.config(text='LED ON')

root = Tk()

root.wm_title('LED on & off program')
app = App(root)
root.mainloop()

这完全符合我的要求。

@WoLy感谢您的努力，但我一直在寻找。

值没有通过tkinter中的按钮传递

3 个答案: