Question

我有一个由EOL分隔的键值对列表。我得到了Boost Spirit来做我想要的格式正确的行（即"MyKey : MyValue \r\n MyKey2 : MyValue2"）。

现在我的问题是我想跳过不符合的行。例如：

This is some title line! 
Key1:Value1
Some more gibberish to skip
Key2:Value2

我提出了以下代码，我认为它可以工作，但是生成的映射是空的，解析失败。

在我的KeyRule中，我添加了' - qi :: eol'，以避免在遇到第一个KeyValue分隔符之前吃掉无效行。
在我的ItemRule中，两个PairRule都是可选的，而eol是1或更多可以解决多个分隔线。

我阅读了以下主题： Why does parsing a blank line with Spirit produce an empty key value pair in map? 它通过自定义队长跳过评论行（以＃开头）但在我的 case，我想跳过任何不包含键值分隔符:的行。必须有一些优雅的东西。

#include <iostream>
#include <string>
#include <map>

#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/std_pair.hpp>

namespace qi = boost::spirit::qi;

template <typename Iterator, typename Skipper = qi::blank_type>
struct KeyValueParser : qi::grammar<Iterator, std::map<std::string, std::string>(), Skipper> {
    KeyValueParser() : KeyValueParser::base_type(ItemRule) {
        ItemRule = -PairRule >> *(+qi::eol >> -PairRule) >> -qi::eol;
        PairRule = KeyRule >> ':' >> ValueRule;
        KeyRule = qi::raw[+(qi::char_ - ':' - qi::eol)];
        ValueRule = qi::raw[+(qi::char_ - qi::eol)];
    }
    qi::rule<Iterator, std::map<std::string, std::string>(), Skipper> ItemRule;
    qi::rule<Iterator, std::pair<std::string, std::string>(), Skipper> PairRule;
    qi::rule<Iterator, std::string(), Skipper> KeyRule;
    qi::rule<Iterator, std::string(), Skipper> ValueRule;
};

int main() {
    const std::string input = " Line To Skip! \r\n  My Key : Value \r\n My2ndKey : Long    Value \r\n";

    std::string::const_iterator iter = input.begin(), end = input.end();

    KeyValueParser<std::string::const_iterator> parser;
    typedef std::map<std::string, std::string> MyMap;
    MyMap parsed_map;

    bool result = qi::phrase_parse(iter, end, parser, qi::blank, parsed_map);

    if (result && (iter == end)) {
        std::cout << "Success." << std::endl;
        for (MyMap::const_iterator pIter = parsed_map.begin(); pIter != parsed_map.end(); ++pIter) {
            std::cout << "\"" << pIter->first << "\" : \"" << pIter->second << "\"" << std::endl;
        }
    } else {
        std::cout << "Something failed. Unparsed: ->|" << std::string(iter, end) << "|<-" << std::endl;
    }

    getchar();
    return 0;
}

Answer 1

我能想到的最优雅的是解析一个keyvalue对/可选/，然后是任何乱码直到行尾。

你可以写：

ItemRule  = -PairRule % (*~char_("\r\n") >> eol);

唯一需要注意的是，在胡言乱语中，＆＃34;默认＆＃34;将插入对（空键和值），因此您必须删除该解析后的内容。

编写它（但不太优雅）的等效方法是：

ItemRule  = (hold[PairRule] | omit[ *~char_("\r\n") ]) % eol;

样本

这是一个完整的演示。注意我还在语法中移动了队长知识（这对正确的语法操作至关重要）。

最后，我使用BOOST_SPIRIT_DEBUG来打印调试输出。

Live On Coliru

#define BOOST_SPIRIT_DEBUG
#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/std_pair.hpp>
#include <map>

namespace qi = boost::spirit::qi;

template <typename Iterator>
struct KeyValueParser : qi::grammar<Iterator, std::map<std::string, std::string>()> {
    KeyValueParser() : KeyValueParser::base_type(ItemRule) {

        using namespace qi;

        ItemRule  = skip(blank) [ -PairRule % (*~char_("\r\n") >> eol) ];
        ItemRule  = skip(blank) [ hold[PairRule] | omit[ *~char_("\r\n") ] ] % eol;
        PairRule  = KeyRule >> ':' >> ValueRule;
        KeyRule   = +~char_("\r\n:");
        ValueRule = +~char_("\r\n");

        BOOST_SPIRIT_DEBUG_NODES((ItemRule)(PairRule)(KeyRule)(ValueRule))
    }
  private:
    qi::rule<Iterator, std::map<std::string, std::string>()> ItemRule;
    qi::rule<Iterator, std::pair<std::string, std::string>(), qi::blank_type> PairRule;
    // lexemes
    qi::rule<Iterator, std::string()> KeyRule, ValueRule;
};

int main() {
    const std::string input = R"(
 Line To Skip! 
  My Key : Value 
Some more gibberish to skip
 My2ndKey : Long    Value 
)";

    std::string::const_iterator iter = input.begin(), end = input.end();

    KeyValueParser<std::string::const_iterator> parser;
    std::map<std::string, std::string> parsed_map;

    bool result = qi::parse(iter, end, parser, parsed_map);

    if (result && (iter == end)) {
        std::cout << "Success.\n";

        // drop empty lines:
        parsed_map.erase("");

        for (auto& p : parsed_map)
            std::cout << "\"" << p.first << "\" : \"" << p.second << "\"\n";
    } else {
        std::cout << "Something failed. Unparsed: ->|" << std::string(iter, end) << "|<-\n";
    }
}

打印

Success.
"My Key " : "Value "
"My2ndKey " : "Long    Value "

使用调试信息

<ItemRule>
  <try>\n Line To Skip! \n  M</try>
  <PairRule>
    <try>\n Line To Skip! \n  M</try>
    <KeyRule>
      <try>\n Line To Skip! \n  M</try>
      <fail/>
    </KeyRule>
    <fail/>
  </PairRule>
  <PairRule>
    <try> Line To Skip! \n  My</try>
    <KeyRule>
      <try>Line To Skip! \n  My </try>
      <success>\n  My Key : Value \nS</success>
      <attributes>[[L, i, n, e,  , T, o,  , S, k, i, p, !,  ]]</attributes>
    </KeyRule>
    <fail/>
  </PairRule>
  <PairRule>
    <try>  My Key : Value \nSo</try>
    <KeyRule>
      <try>My Key : Value \nSome</try>
      <success>: Value \nSome more g</success>
      <attributes>[[M, y,  , K, e, y,  ]]</attributes>
    </KeyRule>
    <ValueRule>
      <try>Value \nSome more gib</try>
      <success>\nSome more gibberish</success>
      <attributes>[[V, a, l, u, e,  ]]</attributes>
    </ValueRule>
    <success>\nSome more gibberish</success>
    <attributes>[[[M, y,  , K, e, y,  ], [V, a, l, u, e,  ]]]</attributes>
  </PairRule>
  <PairRule>
    <try>Some more gibberish </try>
    <KeyRule>
      <try>Some more gibberish </try>
      <success>\n My2ndKey : Long   </success>
      <attributes>[[S, o, m, e,  , m, o, r, e,  , g, i, b, b, e, r, i, s, h,  , t, o,  , s, k, i, p]]</attributes>
    </KeyRule>
    <fail/>
  </PairRule>
  <PairRule>
    <try> My2ndKey : Long    </try>
    <KeyRule>
      <try>My2ndKey : Long    V</try>
      <success>: Long    Value \n</success>
      <attributes>[[M, y, 2, n, d, K, e, y,  ]]</attributes>
    </KeyRule>
    <ValueRule>
      <try>Long    Value \n</try>
      <success>\n</success>
      <attributes>[[L, o, n, g,  ,  ,  ,  , V, a, l, u, e,  ]]</attributes>
    </ValueRule>
    <success>\n</success>
    <attributes>[[[M, y, 2, n, d, K, e, y,  ], [L, o, n, g,  ,  ,  ,  , V, a, l, u, e,  ]]]</attributes>
  </PairRule>
  <PairRule>
    <try></try>
    <KeyRule>
      <try></try>
      <fail/>
    </KeyRule>
    <fail/>
  </PairRule>
  <success></success>
  <attributes>[[[[], []], [[M, y,  , K, e, y,  ], [V, a, l, u, e,  ]], [[M, y, 2, n, d, K, e, y,  ], [L, o, n, g,  ,  ,  ,  , V, a, l, u, e,  ]]]]</attributes>
</ItemRule>

提升精神 - 在键值对中跳过不需要的线条

1 个答案:

样本