我目前正在使用4个查询来获取4个不同时间范围内的出现次数。
jquery.ui
我认为必须有一种方法将这些合并到一个查询中。有什么想法吗?
答案 0 :(得分:3)
组合查询的更好方法
SELECT CASE
WHEN time > A AND time < B THEN 'A-B'
WHEN time > B AND time < C THEN 'B-C'
WHEN time > C AND time < D THEN 'C-D'
WHEN time > D AND time < E THEN 'D-E'
END,
Count(*)
FROM yourtable
WHERE keyword = 'keyword'
AND time > A
AND time < E
GROUP BY CASE
WHEN time > A AND time < B THEN 'A-B'
WHEN time > B AND time < C THEN 'B-C'
WHEN time > C AND time < D THEN 'C-D'
WHEN time > D AND time < E THEN 'D-E'
END
答案 1 :(得分:0)
您可以使用union
:
SELECT 'AB', count(*) WHERE keyword='keyword' AND time>A AND time<B;
UNION
SELECT 'BC', count(*) WHERE keyword='keyword' AND type>B AND time<C;
UNION
SELECT 'CD', count(*) WHERE keyword='keyword' AND type>C AND time<D;
UNION
SELECT 'DE', count(*) WHERE keyword='keyword' AND type>D AND time<E;