从Poly / ML中的源代码字符串获取解析树

时间:2016-02-23 16:26:52

标签: sml polyml

我正在尝试编译一串源代码并使用Poly / ML打印解析树。以下代码编译,但解析树为空:

fun main () =
    let
        val stream = TextIO.openString "let val a = \"abc\"; val b = \"def\"; val c = a ^ b in print c end";
        val _ = PolyML.compiler (fn () => TextIO.input1 stream, []);
        val (_, parseTree) = !PolyML.IDEInterface.parseTree
    in
        PolyML.print (parseTree);
        PolyML.print (List.length parseTree);
        List.map PolyML.print (parseTree);
        ()
    end

运行此:

$ ./a.out
[...]
0
$

从编译器获取解析树需要做什么?我还尝试使用CPCompilerResultFun编译器参数进行变体。但这也不起作用:

fun main () =
    let
        fun useTree (NONE, _) () =
            (PolyML.print "not parsed"; ())
          | useTree (SOME parseTree, _) () =
            (PolyML.print "parsed"; PolyML.print parseTree; ());

        val stream = TextIO.openString "let val a = \"abc\"; val b = \"def\"; val c = a ^ b in print c end";
        val _ = PolyML.compiler (fn () => TextIO.input1 stream, [PolyML.Compiler.CPCompilerResultFun useTree]);
    in
        ()
    end

运行它不会产生任何输出。

1 个答案:

答案 0 :(得分:3)

我能够通过提供PolyML.Compiler.CPCompilerResultFun编译器选项来获取它。它允许你access and save the parse tree。但是,我不能过多地说出解析树是如何实际表示的。有一些文档here(网站对我来说不起作用),但我还没有太多意义。

val resultTrees : PolyML.parseTree list ref = ref [];

fun compilerResultFun (parsetree, codeOpt) =
  let
    val _ =
      case parsetree of
        SOME pt => resultTrees := !resultTrees @ [pt]
      | NONE => ()
  in
    fn () => raise Fail "not implemented"
  end;

val stream = TextIO.openString "val a = 1";

val _ = PolyML.compiler (fn () => TextIO.input1 stream, [
  PolyML.Compiler.CPCompilerResultFun compilerResultFun
]);

val [(a, [PolyML.PTfirstChild b])] = !resultTrees;
val (_, [PolyML.PTfirstChild c, PolyML.PTparent d, PolyML.PTprint e]) = b ();