Question

我无法弄清楚为什么我要用字符串文件名编译错误;它说它“超出范围”我尝试使用cstrings但是没有用，我从教科书中复制了一个基本的字符串示例代码，甚至没有编译。

#include <iostream>
#include <fstream>
#include <iomanip>
#include <string>
using namespace std;
int main()
{
ifstream file1;

// setting variables up for calculation
string filename;
float average, x;
float total = 0;
float count = 0;
float min = 0;
float max = 0;


//asking for file name
cout << "What is the name of the file you wish to open" << endl;
getline(cin, filename);

// opening file
file1.open(filename);
if (file1.fail())
{
cout << "Failure to open that file, please try again." << endl;
return 0;
}

//reading file 
if (file1.is_open())
{   
while (file1 >> x)
{
    if (x <= min)
    { x = min;
    }
    if (x >= max)
    { x = max;
    }
    total = total + x;
    count++;
    if (file1.eof())
    { break;
    }
}
}
// final calculations and testing 
average = (total / average);
cout << "Minimum = " <<  min << endl;
cout << "Maximmum = " << max << endl;
cout << "The total count = " << count << endl;
file1.close();
return 0;
}

Answer 1

在C ++ 11之前，文件流仅将const char*作为文件名。对于C ++ 11，std::string也存在重载。如果您没有重载，请在调用filename.c_str()时使用open来获取指向内容为filename的C字符串的指针。

我不能让这个字符串在C ++中工作

1 个答案: