Question

我想用以下模式拆分字符串：

abc3xab     -> ('abc', '3xa', 'b')
abc3x3xab   -> ('abc', '3x3x', 'ab')
abc3xxab    -> ('abc', '3xx', 'ab')
abc34xxab   -> ('abc', '34xx', 'ab')
abc100ab    -> ('abc100ab')
abc10axb    -> ('abc10axb')

就是这样，模式是'[0-9] + x [a-z]'（如果有一个数字后跟'x'和a-z之间的任何字符。我试过了

String[] words = string.split("[0-9]+x")

然后我只有abc和ab。这样做的正确方法是什么？

Answer 1

尝试使用正向前瞻和后瞻的组合来保留分隔符：

String[] words = string.split("((?<=[0-9]+x)|(?=[0-9]+x))");

Sample IDEONE demo：

String[] words = "abc3xab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words));
String[] words1 = "abc3xxab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words1));
String[] words2 = "abc34xxab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words2));
String[] words3 = "abc100ab".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words3));
String[] words4 = "abc10axb".split("((?<=[0-9]+x)|(?=[0-9]+x))");
System.out.println(Arrays.toString(words4));

结果：

[abc, 3x, ab]
[abc, 3x, xab]
[abc, 3, 4x, xab]
[abc100ab]
[abc10axb]

基于数字/字符模式拆分字符串 - Java

1 个答案: