Question

我正在研究一个类的问题，我们正在学习C中的链表。我得到了一段代码来完成，特别是删除一个节点部分，我在删除头部时遇到了问题。每当我尝试删除头部时，我都会收到分段错误。有人能告诉我我做错了吗？

EDIT2 我的老师写了除查找和删除功能以外的所有内容。

我已经解决了莫斯科先生和Petriuc先生指出的明显错误，但是代码仍未运行。它确实可以编译，但是头部仍然存在问题。

以下是完整代码：

#include <string.h>
#include <stdio.h>
#include <stdlib.h>

#include "linkedList.h"

// keep an unsorted array of char *'s, strings.

/*
  Create an empty node, return 0 if fail, 1 if succeed
 */
struct node * createNode() {
  struct node *p = (struct node *) malloc(sizeof(struct node));
  if (p == NULL) return 0;

  p->prev = p->next = NULL;
  p->data = NULL;
}


/*
  Lookup string in the list, return pointer to node of first occurence, NULL if not found.
 */
struct node * lookup(struct node *head, char *s) {
  struct node *p;
  for(p=head; p!=NULL; p=p->next){
    if(strcmp(s,p->data)==0){
      return p;
    }
  // just like print, but check if strcmp(s, p->data) == 0, and if so then return p
  }
  return NULL;
}


/*
  Insert new string into the linked list, return 1 if success, 0 if fail.
 */
int insert(struct node **head, char *newS, int insertDuplicate) {
  struct node *p = lookup(*head, newS);

  if (p == NULL || insertDuplicate) {
    // create a new node, put it at the front.
    p = createNode();
    if (p == NULL) return 0;

    // put the string in the new node
    p->data = (char *) malloc(sizeof(char) * (1 + strlen(newS)));
    if (p->data == NULL) return 0;
    strcpy(p->data, newS);

    // note: make changes and use old head before setting the new head...
    p->next = *head;   // next of new head is previous head

    if (*head != NULL)
      (*head)->prev = p; // previous of old head is new head

    *head = p;         // set the new head
  }

  return 1;
}

/*
  Remove string from list if found, return 1 if found and deleted, 0 o/w.
 */
int delete(struct node **head, char *s) {
  struct node *p,*pr,*ne;
  // first do a lookup for string s, call lookup.
  p=lookup(*head, s);

  if(p==*head){
    *head = p->next;
    free(p);
    return 1;
  }

  if(p!=NULL){
     printf("%s",p);
     pr = p->prev;
     ne = p->next;

     free(p->data);
     free(p);

    if(pr==NULL||ne==NULL){
      return 0;
    }
     pr->next=ne;
     ne->prev=pr;
  // if lookup returns NULL, done, return 0.
  // if lookup returns p, not NULL,
  // pr = p->prev, ne = p->next
  //  set pr->next to ne, ne->prev to pr
  //  but what if pr or ne is NULL
  // and note that we need node **head because if delete head,
  // need to update head pointer back in calling function, in
  // here if you want head probably do *head.  like in insert.
  // also, before the pointer to the one you're deleting is gone,
  // free p->data and p.
    return 1;
  }
  return 0;
}


void print(struct node *head) {
  struct node *p;
  for(p = head; p != NULL ; p = p->next) {
    printf("%s\n", p->data);
  }
}

Answer 1

你在做什么

p-＆gt; next = * head;

但p未分配到任何地方。

Answer 2

你的功能没有意义。你可以调用函数lookup三次。

此外，您使用未初始化的指针，例如

p->next = *head;

或

printf("%s",p);
pr = p->prev;
ne = p->next;

该功能可以按以下方式编写

int delete( struct node **head, char *s ) 
{
    int success;
    struct node *target = lookup( *head, s );

    if ( ( success = target != NULL ) )
    {
        if ( target->prev != NULL )
        {
            target->prev->next = target->next;
        }
        else
        {
            *head = target->next;
        }

        if ( target->next != NULL )
        {
            target->next->prev = target->prev );
        }

        free( target );
    }        

    return success;
}

考虑到函数的第二个参数和函数查找的相应参数应该用限定符const声明

int delete( struct node **head, const char *s ) ;
                                ^^^^^
struct node * lookup( struct node *head, const char *s );
                                         ^^^^^^

Answer 3

简化删除（）函数。我内联了lookup（），因为它的功能是没有价值的（你需要一个指向指针的指针，而不是一个指针来处理）

/*
  Remove string from list if found, return 1 if found and deleted, 0 o/w.
 */
int delete(struct node **head, char *s) {
  struct node *tmp;

      // first do a lookup for string s, no need to call call lookup.
  for( ;*head; head = &(*head)->next ){
    if (!strcmp( (*head)->data, s)) break;
    }
  if (!*head) return 0; // not found

  tmp = *head
  *head = tmp->next
  free(tmp);
  return 1;
  }

C - 链接列表 - 删除头部 - 分段错误

3 个答案: