我正在尝试使用变量INSERT
将新行添加到表中,如下所示 -
$name = $_POST['name'];
$surname = $_POST['surname'];
$email = $_POST['email'];
$password = $_POST['password'];
$gender = $_POST['gender'];
if($name && $surname && $email && $password){
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = '_erica';
$conn = new mysqli($dbhost, $dbuser, $dbpass,$db);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
};
$sql = 'INSERT INTO login(id, name, surname, email, sex, password) VALUES (Null,$name,$surname,$email,$gender,$password)';
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
}else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}else{
die('All fields requiret!');
};
但是它不起作用,我试图在像这样的变量中添加引号
$sql = 'INSERT INTO login(id, name, surname, email, sex, password) VALUES(Null,"$name","$surname","$email","$gender","$password")';
仍然没有...我该怎么办?
答案 0 :(得分:1)
试试这个,
$sql = 'INSERT INTO login(id, name, surname, email, sex, password) VALUES(NULL,"'.$name.'","'.$surname.'","'.$email.'","'.$gender.'","'.$password.'")';
或(使用双引号而不是单引号)
$sql = "INSERT INTO login(id, name, surname, email, sex, password) VALUES(NULL,$name,$surname,$email,$gender,$password)";
答案 1 :(得分:1)
使用它。只需更改带双引号的单引号
$sql = "INSERT INTO login(id, name, surname, email, sex, password) VALUES (Null,$name,$surname,$email,$gender,$password)";