我的表格包含以下表格,其中包含群组及其成员。
+---------+----+-------+
| group | p | state |
+---------+----+-------+
| group a | p1 | 3 |
| group a | p2 | 1 |
| group a | p3 | 0 |
| group a | p4 | 3 |
| group b | p1 | 1 |
| group b | p2 | NULL |
| group b | p3 | 3 |
| group c | p2 | 1 |
| group c | p3 | NULL |
| group c | p4 | 3 |
+---------+----+-------+
我想获取p1
所属的所有群组及其成员。
我想出了这个
select group, p from `groups` where group in (select DISTINCT group from `groups` where p = "p1")
每个组的比例约为100,000个用户,用户可以是任意数量的组的一部分。 有没有更有效的方法呢?
答案 0 :(得分:0)
您可以尝试自我加入:
//Creating a new calendar
net.fortuna.ical4j.model.Calendar calendar = new net.fortuna.ical4j.model.Calendar();
calendar.getProperties().add(new ProdId("-//Ben Fortuna//iCal4j 1.0//EN"));
calendar.getProperties().add(Version.VERSION_2_0);
calendar.getProperties().add(CalScale.GREGORIAN);
TimeZoneRegistry registry = TimeZoneRegistryFactory.getInstance().createRegistry();
TimeZone timezone = registry.getTimeZone("Etc/GMT");
//Creating an event
java.util.Calendar startCal = java.util.Calendar.getInstance(timezone);
startCal.set(java.util.Calendar.YEAR, 2005);
startCal.set(java.util.Calendar.MONTH, java.util.Calendar.NOVEMBER);
startCal.set(java.util.Calendar.DAY_OF_MONTH, 1);
startCal.set(java.util.Calendar.HOUR_OF_DAY, 15);
startCal.clear(java.util.Calendar.MINUTE);
startCal.clear(java.util.Calendar.SECOND);
java.util.Calendar endCal = java.util.Calendar.getInstance(timezone);
endCal.set(java.util.Calendar.YEAR, 2005);
endCal.set(java.util.Calendar.MONTH, java.util.Calendar.NOVEMBER);
endCal.set(java.util.Calendar.DAY_OF_MONTH, 1);
endCal.set(java.util.Calendar.HOUR_OF_DAY, 19);
endCal.clear(java.util.Calendar.MINUTE);
endCal.clear(java.util.Calendar.SECOND);
net.fortuna.ical4j.model.DateTime dtStart = new DateTime (startCal.getTime());
dtStart.setUtc(true);
net.fortuna.ical4j.model.DateTime dtEnd = new DateTime (endCal.getTime());
dtEnd.setUtc(true);
VEvent event = new VEvent(dtStart,dtEnd, "Test Event");
答案 1 :(得分:0)
如果'p1'只能出现在每个组中,那么您可以进行简单的连接: -
snprintf