我在模型中添加了一个属性并返回页面。在admin.html页面中，我遍历所有用户并显示详细信息。但我想将一个用户从列表中返回"/admin/showReports"。
我希望有人可以帮助我。我真的被困了。
@RequestMapping(value = "/admin")
public String showAllUser(Model model) {
model.addAttribute("allUser",userDelegate.getAllUser());
return "admin";
}
@RequestMapping(value = "/admin/showReports", method = RequestMethod.POST)
public String showAllAvailableReportsForUser(Model model, User user) {
model.addAttribute("user", user);
model.addAttribute("reports", userDelegate.getAllReports());
return "addReports";
}
<!DOCTYPE html>
<html xmlns:th="http://www.thymeleaf.org">
<head>
<title>Admin</title>
<link rel="stylesheet" href="/webjars/bootstrap/3.3.6/css/bootstrap.css"/>
<script src="/webjars/bootstrap/3.3.6/webjars-requirejs.js"></script>
</head>
<body>
<h1>Admin</h1>
<div class="container">
<div class="col-md-1"></div>
<div class="panel panel-default col-md-10">
<div class="panel-heading">User</div>
<table class="table">
<tr>
<th>Id</th>
<th>Username</th>
<th>E-mail</th>
<th>Reports</th>
</tr>
<tr th:each="user : ${allUser}">
<td th:text="${user.identifier}"></td>
<td th:text="${user.username}"></td>
<td th:text="${user.email}"></td>
<td th:text="${user.reports}"></td>
<form th:action="@{/admin/showReports}" method="post">
<td>
<!--Here is the Problem. How do i return one user from the list?-->
<input type="hidden" th:value="${user}" />
<button type="submit">edit</button>
</td>
</form>
</tr>
</table>
</div>
<div class="col-md-1"></div>
</div>
</body>
</html>
@Bean
public SpringResourceTemplateResolver templateResolver(){
SpringResourceTemplateResolver resolver = new SpringResourceTemplateResolver();
resolver.setPrefix("classpath:/templates/");
resolver.setSuffix(".html");
resolver.setTemplateMode("HTML5");
resolver.setOrder(1);
return resolver;
}
@Bean
public SpringTemplateEngine templateEngine() {
SpringTemplateEngine engine = new SpringTemplateEngine();
engine.setTemplateResolver(templateResolver());
engine.addDialect(new LayoutDialect());
return engine;
}
@Bean
public ThymeleafViewResolver thymeleafViewResolver() {
ThymeleafViewResolver resolver = new ThymeleafViewResolver();
resolver.setTemplateEngine(templateEngine());
return resolver;
}
答案 0 :(得分：1)
您可以通过网址传递唯一标识符来解决问题。
通过id的示例，请注意对GET的更改，因此只需放置一个链接而不是表单。
@RequestMapping(value = "/admin/showReports/{id}", method = RequestMethod.GET)
public String showAllAvailableReportsForUser(Model model, @PathVariable("id") Long id) {
User user = userDelegate.getUserById(id); // Get user via id
mav.addObject("user", user);
// Get and add whatever else you need
return "addReports";
}