Question

试图理解为什么在加载此页面时，$ member [＆＃39; memberName＆＃39;]和$ member [＆＃39; memberDOB＆＃39;]对象没有值。提前感谢任何帮助，仍在学习php和MySQL。：）

这是HTML：

z-index

PHP：

<table>
        <tr>
            <th>Player Name</th>
            <th>Player Date of Birth</th>
        </tr>
        <?php foreach ((array)$members as $member) : ?>
        <tr>
            <td><?php echo $member['memberName']; ?></td>
            <td><?php echo $member['memberDOB']; ?></td>
        </tr>
        <?php endforeach; ?>

    </table>

以下是功能：

} else if ($action == 'view_team_members') {
$team_id = filter_input(INPUT_GET,'team_id');
$team_name = get_team_name($team_id);
$members = get_team_members($team_id);
include('/view/team_members.php');
}

Answer 1

在玩了几个小时后，我将fetch（）更改为fetchAll（） - 这解决了问题（同时删除了closeCursor（））。

function get_team_members($team_id) {
global $db;
$query = 'SELECT * FROM members
      WHERE teamID = :team_id';
$statement = $db->prepare($query);
$statement->bindValue(':team_id', $team_id);
$statement->execute();
$members = $statement->fetchAll();
return $members;
}

PHP没有传递的价值

1 个答案: