Question

此查询将在SQL中按月和年分组。我想要针对此问题的选择查询，其中用户将输入FromDate和ToDate：

我正在测试的查询：

select 
    year(CDate) as Payment_year, 
    count(distinct CDate) as count_days,
    month(CDate) as month_name,
    isnull(sum(Amount),0.00) as Total_Amount 
from 
    tblCowMilk
where 
    CDate between '2016-01-01' and '2016-03-31' 
group by 
    year(CDate),
    month(CDate),
    (datepart(day,CDate))/11 
order by 
    month_name

enter image description here

我想要一个像这样的结果

                    Payment Register for the Period: 01-05-2015 to 23-02-2016         
 -----------------------------------------------------------------------------------------
 MONTH      days      I PERIOD    days   II PERIOD   day   III PERIOD      TOTAL  
 -----------------------------------------------------------------------------------------
May           10         10.00     10      160.00       11       0.00         170.00

June                     30.00               0.00                0.00          30.00

July                     20.00               0.00               10.00          30.00

August                    0.00               0.00                0.00           0.00

September                10.00               0.00                0.00          10.00

October                   0.00               0.00                0.00           0.00

November                  0.00               0.00                0.00           0.00

December                  0.00               0.00                0.00           0.00

January                   0.00               0.00                0.00           0.00

February                  0.00               0.00                0.00           0.00
-----------------------------------------------------------------------------------------
                         70.00             160.00               10.00         240.00
-----------------------------------------------------------------------------------------

Answer 1

您计算10天组的逻辑是错误的，目前它是

1-10
11-21
22-end of month

这应该返回正确的结果：

select 
    year(CDate) as Payment_year, 
    count(* as count_days,
    month(CDate) as month_name,
    sum(case when period = 1 then Total_Amount else 0 end) as Period_I,
    sum(case when period = 2 then Total_Amount else 0 end) as Period_II,
    sum(case when period = 3 then Total_Amount else 0 end) as Period_III,
    isnull(sum(Total_Amount),0.00) as Total_Amount
from
 (
   select 
      CDate,
      case -- 10 days within a period
         when datepart(day,CDate) <= 10 then 1
         when datepart(day,CDate) <= 20 then 3
         else 3
      end as period,
     sum(Amount) as Total_Amount
   from 
      tblCowMilk
   where 
      CDate between '2016-01-01' and '2016-03-31' 
   group by 
      CDate,
      case
         when datepart(day,CDate) <= 10 then 1
         when datepart(day,CDate) <= 20 then 3
         else 3
      end
 ) as dt
group by year(CDate), month(CDate)
order by year(CDate), month(CDate)

要获得Grand Total，您需要标准SQL的扩展分组，我不知道SQL Server 2012是否完全支持这一点：

group by
   grouping sets ((year(CDate),month(CDate)),())
order by
   grouping(year(CDate)), year(CDate),
   grouping(month(CDate)), month(CDate)

或者在你的申请中做总计。

Answer 2

试试这个

select 
    year(a.CDate) as Payment_year, 
    month(a.CDate) as month_name,
    COUNT(b.Amount) as 'I Period',
    COUNT(c.Amount) as 'II Period',
    COUNT(d.Amount) as 'II Period',
    isnull(sum(a.Amount),0.00) as Total_Amount 
from 
    tblCowMilk a 
left join tblCowMilk d on d.CDate = a.CDate and DAY(d.CDate) < 11
left join tblCowMilk b on b.CDate = a.CDate and DAY(b.CDate) >10  and DAY(b.CDate) <21
left join tblCowMilk c on c.CDate = a.CDate  and DAY(c.CDate) >20
where 
    a.CDate between '2016-01-01' and '2016-03-31' 

group by 
    year(a.CDate),
    month(a.CDate),
order by 
    month_name

如何在SQL中的前10天，后10天和一个月的剩余日中拆分月份

2 个答案: