Question

我有一个像这样设置的表

Project   Category   Date       Hours
Proj1     test       8/2/2010   2
Proj1     test       8/3/2010   8
Proj1     test       8/4/2010   4
Proj1     test       8/5/2010   3
Proj1     test       8/6/2010   5

我想开发一个查询，您可以输入星期六（周结束日期）并获得这样的结果

WeekEnding Project Category  SunHrs MonHrs TuesHrs WedHrs ThuHrs FriHrs SatHrs  
8/7/2010   Proj1   test      0      2      8       4      3      5      0

谢谢

Answer 1

一些好文章可以提供帮助：

http://www.devx.com/dbzone/Article/28165

http://technet.microsoft.com/en-us/library/ms177410.aspx

Answer 2

这是一种方式。它看起来很像kludgey，但是那时的枢轴总是看起来像那样。

DECLARE @Saturday datetime

SET @Saturday = 'Aug 7, 2010'

SELECT
   @Saturday       WeekEnding
  ,Project
  ,Category
  ,isnull([1], 0)  SunHrs
  ,isnull([2], 0)  MonHrs
  ,isnull([3], 0)  TueHrs
  ,isnull([4], 0)  WedHrs
  ,isnull([5], 0)  ThuHrs
  ,isnull([6], 0)  FriHrs
  ,isnull([7], 0)  SatHrs
 from (select Project, Category, Datepart(dw, Date) DOW, Hours
        from MyTable
        --  Fixed bug from -7 to -6
        where Date between dateadd(dd, /*-7*/ -6, @Saturday) and @Saturday) Source
  pivot (max(Hours)
         for DOW in ([1],[2],[3],[4],[5],[6],[7]) ) as pvt

我使用以下内容设置数据来测试：

DROP TABLE MyTable
CREATE TABLE MyTable
 (
    Project    varchar(10)  not null
   ,Category   varchar(10)  not null
   ,Date       datetime     not null
   ,Hours      int          not null
 )

INSERT MyTable
 values 
('Proj1', 'test', '8/2/2010',  2 ),
('Proj1', 'test', '8/3/2010',  8 ),
('Proj1', 'test', '8/4/2010',  4 ),
('Proj1', 'test', '8/5/2010',  3 ),
('Proj1', 'test', '8/6/2010',  5 )

SQL Server 2005查询以透视数据

2 个答案: