所以我这里有一个角度代码来获取json记录。一切顺利。但它不会显示在视图上。我希望json结果显示在选择标记上,这里是视图部分的代码
<div class="col s6 input-field" ng-controller="positionController">
<select id="selectPosition" ng-model="selectedPosition" ng-options="item as item.PosDesc for item in records">
</select>
<label>Choose Position</label>
</div>
但它并没有在视图上显示任何内容。我的代码有问题吗?谢谢。
答案 0 :(得分:1)
您的代码运行正常。
查看此演示。
(function() {
var app = angular.module("app", []);
app.filter("capitalize", function() {
return function(input, all) {
var reg = (all) ? /([^\W_]+[^\s-]*) */g : /([^\W_]+[^\s-]*)/;
return (!!input) ? input.replace(reg, function(txt) {
return txt.charAt(0).toUpperCase() + txt.substr(1).toLowerCase();
}) : "";
};
});
app.controller("positionController", ["$scope", "$http",
function($scope, $http) {
$http.get("https://gist.githubusercontent.com/dannyjhonston/dfbb68cffa626c2e29b3/raw/5c6fc8c1f7529fe25a6a848e9154c5b778dd3eb3/jsonFile.json").success(function(response) {
$scope.records = response;
$scope.selectedPosition = $scope.records[0];
});
}
]);
})();
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div data-ng-app="app">
<div class="col s6 input-field" ng-controller="positionController">
<select id="selectPosition" ng-model="selectedPosition" ng-options="item as item.PosDesc for item in records">
</select>
<label>Choose Position</label>
</div>
</div>
&#13;
答案 1 :(得分:0)
更改ng-model =&#34; selectedPosition&#34;到ng-model =&#34;(selectedPosition | json)&#34;。要在选择中使用角度代码,如:
<select id="selectPosition" ng-model="(selectedPosition | json)"
ng-options="item as item.PosDesc for item in records">
{{ selectedPosition | json }}
</select>