Question

我收到语法错误代码1并且无法解决它..当我尝试从db获取数据时我得到此错误。我看起来一切似乎都没问题。我正在使用putExtra（）和getExtras（）来获取变量并按它排序。这是我的错误代码。这是我的Dbhandler，光标线上有错误。

private static final String DATABASE_NAME = "Log.db";

    //table name
    public static final String TABLE_LOGS = "Logs";
    //TableLogs column names
    public static final String KEY_ID = "id";
    public static final String KEY_PLATENUMBER = "platenumber";
    public static final String KEY_PLACE = "place";
    public static final String KEY_SORT = "sortid";
    public static final String KEY_GRADE = "grade";
    public static final String KEY_DIAMETER = "diameter";
    public static final String KEY_LENGTH = "length";
    public static final String KEY_CREATED_AT ="created_at";

    public LogsDBHandler(Context context){
        super(context, DATABASE_NAME, null, DATABASE_VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        String CREATE_LOGS_TABLE = "CREATE TABLE " + TABLE_LOGS + " (" +
                KEY_ID + " INTEGER PRIMARY KEY AUTOINCREMENT," +
                KEY_CREATED_AT + " TIMESTAMP DEFAULT CURRENT_DATE,"+
                KEY_PLACE+ " TEXT, "+
                KEY_PLATENUMBER + " TEXT, " +
                KEY_SORT + " TEXT, "+
                KEY_GRADE+ " TEXT, "+
                KEY_DIAMETER + " TEXT, " +
                KEY_LENGTH + " TEXT);";
        db.execSQL(CREATE_LOGS_TABLE);
    }
 public ArrayList<Logs> getAllLogsWithSamePlace(String place) {
        ArrayList<Logs> logPlaceList = new ArrayList<Logs>();
        String selectQuery = "SELECT " + KEY_PLACE + " FROM " + TABLE_LOGS + " WHERE " + KEY_PLACE + " =? " + place;

        SQLiteDatabase db = this.getWritableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null); //in this line error

        if (cursor.moveToFirst()) {
            do {
                Logs log = new Logs();
                log.setId(cursor.getLong(0));
                log.setPlate_number(cursor.getString(1));
                log.setSort_id(cursor.getString(2));
                log.setGrade(cursor.getString(3));
                log.setDiameter(cursor.getString(4));
                log.setLength(cursor.getString(5));
            }while (cursor.moveToNext());
        }
        return  logPlaceList;
    }

这是我的putExtra（）

的鳕鱼

mainListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                Intent intent = new Intent(DisplayLogsByPlace.this, LogsList.class);
                intent.putExtra("keyPlace", logsList.get(position).getPlace());
                startActivity(intent);
            }
        });

最后我的getExtras（）代码在arrayList行上有错误

  String place = (String) getIntent().getExtras().get("keyPlace");
        dbHandler = new LogsDBHandler(this);
        ArrayList<Logs> logsList = dbHandler.getAllLogsWithSamePlace(place); //error here

这里是有错误的日志

2-22 23:00:52.980 10278-10278/ E/SQLiteLog: (1) near "London": syntax error
02-22 23:00:52.990 10278-10278/ W/dalvikvm: threadid=1: thread exiting with uncaught exception (group=0x4111d540)
02-22 23:00:53.030 10278-10278/ E/AndroidRuntime: FATAL EXCEPTION: main
                                                                        java.lang.RuntimeException: Unable to start activity ComponentInfo{.LogsList}: android.database.sqlite.SQLiteException: near "London": syntax error (code 1): , while compiling: SELECT place FROM Logs WHERE place =? London

我检查所有代码，对我来说似乎没问题。

Answer 1

如果您将查询值作为参数?传递，那么您不应该在null

的第二个参数处传递rawQuery()

String selectQuery = "SELECT " + KEY_PLACE + " FROM " + TABLE_LOGS + " WHERE " + KEY_PLACE + "=?" ;
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, new String[]{place});

访问rawQuery (String sql, String[] selectionArgs)

Answer 2

也许是因为“？”符号在何处=？你可以删除它并再次运行吗？

SQLiteLog语法错误代码1 - android

2 个答案: